Categoria per defecte en Matemàtiques - 4t dESO ► Equacions ► Eq. primer grau ► Equacions de primer grau ► Equacions amb denominadors (calculada)
- Equacions amb denominadors 55
$$ \frac{-10 + 2 x } {2} = \frac{-2 x + 3} {-3} $$- $$ \frac{-11 + 5 x } {-2} = \frac{2 x + 11} {-3} $$
- $$ \frac{-12 - 8 x } {-4} + \frac{3 - 7 x } {4} = 3 x + 12 $$
- $$ \frac{-12 + 3 x } {4} = \frac{8 - 4 x } {-4} $$
- $$ \frac{-14 - 3 x } {-2} = \frac{4 - 2 x } {-4} $$
- $$ \frac{-19 x + 1} {2} + \frac{-22 + 2 x } {-2} = 14 - 13 x $$
- $$ \frac{-2 x - 10} {-4} + \frac{2 x + 4} {-3} = 2 x + 25 $$
- $$ \frac{-2 x - 16} {-3} = \frac{-2 x - 8} {-2} $$
- $$ \frac{-2 x - 4} {-2} + \frac{-3 x - 1} {2} = 2 x - 16 $$
- $$ \frac{-2 x + 14} {3} + \frac{-2 x - 2} {-2} = 2 x - 11 $$
- $$ \frac{-2 x + 2} {-4} = \frac{3 x + 5} {4} $$
- $$ \frac{-2 x + 8} {-6} = \frac{-14 + 2 x } {3} $$
- $$ \frac{-23 x + 8} {5} = \frac{20 x - 2} {-6} $$
- $$ \frac{-3 + 3 x } {-12} + \frac{-2 x + 8} {2} = -1 - 2 x $$
- $$ \frac{-3 x - 5} {-5} + \frac{1 - 3 x } {-2} = -14 + 5 x $$
- $$ \frac{-3 x - 8} {-2} + \frac{3 x + 12} {-3} = 2 x + 12 $$
- $$ \frac{-4 - 2 x } {-4} = \frac{-2 x - 9} {-3} $$
- $$ \frac{-4 + 4 x } {-3} = \frac{-5 x - 9} {2} $$
- $$ \frac{-4 + 4 x } {3} + \frac{-5 x - 1} {-7} = 4 x - 9 $$
- $$ \frac{-6 + 12 x } {-2} = \frac{-10 + 8 x } {-2} $$
- $$ \frac{-6 + 2 x } {-3} = \frac{-6 - 2 x } {6} $$
- $$ \frac{10 - 4 x } {-11} = \frac{-2 + 6 x } {10} $$
- $$ \frac{10 + 4 x } {-6} + \frac{-2 x + 22} {2} = -4 + 5 x $$
- $$ \frac{12 - 4 x } {-2} = \frac{2 x + 6} {3} $$
- $$ \frac{13 - 2 x } {7} + \frac{-2 x - 24} {-2} = -9 - 5 x $$
- $$ \frac{15 x - 9} {2} + \frac{25 x + 9} {-4} = 8 + 16 x $$
- $$ \frac{2 x - 1} {3} + \frac{2 - 2 x } {-2} = -5 + 2 x $$
- $$ \frac{2 x - 2} {-7} = \frac{-6 - 4 x } {9} $$
- $$ \frac{2 x - 4} {-6} + \frac{3 x - 6} {2} = 3 x - 17 $$
- $$ \frac{2 x - 4} {-6} = \frac{-2 x - 4} {4} $$
- $$ \frac{2 x + 10} {-3} = \frac{-3 x - 3} {3} $$
- $$ \frac{2 x + 12} {3} + \frac{-12 - 2 x } {6} = 22 + 2 x $$
- $$ \frac{2 x + 4} {-7} + \frac{2 x + 6} {3} = -2 x - 20 $$
- $$ \frac{2 x + 4} {2} = \frac{-2 x + 3} {-3} $$
- $$ \frac{2 x + 4} {5} = \frac{8 + 2 x } {6} $$
- $$ \frac{2 x + 6} {3} + \frac{2 + 2 x } {-2} = 3 x - 19 $$
- $$ \frac{2 x + 7} {-25} + \frac{4 + 2 x } {-2} = 6 - 2 x $$
- $$ \frac{25 + 3 x } {2} + \frac{5 x + 5} {-2} = 2 x + 25 $$
- $$ \frac{3 - 2 x } {-7} + \frac{2 x - 12} {3} = 2 x - 17 $$
- $$ \frac{3 - 2 x } {5} = \frac{12 + 2 x } {-2} $$
- $$ \frac{4 - 2 x } {-4} + \frac{-2 x + 2} {-2} = 3 + 2 x $$
- $$ \frac{4 x + 2} {-7} + \frac{-12 - 2 x } {-3} = 4 x - 8 $$
- $$ \frac{6 + 4 x } {-9} + \frac{-4 - 3 x } {-2} = 4 x + 19 $$
- $$ \frac{7 - 2 x } {-5} = \frac{-2 x + 1} {-7} $$
- $$ \frac{7 x - 1} {-3} + \frac{6 x - 12} {-4} = 1 - 5 x $$
- $$ \frac{7 x + 8} {-2} = \frac{-12 x + 2} {2} $$
- $$ \frac{8 x - 5} {-3} = \frac{4 x - 13} {-3} $$
- $$ \frac{9 - 8 x } {3} = \frac{16 + 3 x } {-5} $$
- Equacions amb denominadors (calculada) 7
