/ polinoame 1 Fie polinomul P(X)=#P.

1. Soluţiile ecuaţiei P(x)=0 în «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi mathvariant=¨normal¨»§#8450;«/mi»«/math» sunt:

x1={#1}

x2={#2}

x3={#3}

x4={#4}.

a) Valoarea expresiei «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«msub»«mi»x«/mi»«mn»1«/mn»«/msub»«mn»2«/mn»«/msup»«mo»+«/mo»«msup»«msub»«mi»x«/mi»«mn»2«/mn»«/msub»«mn»2«/mn»«/msup»«mo»+«/mo»«msup»«msub»«mi»x«/mi»«mn»3«/mn»«/msub»«mn»2«/mn»«/msup»«mo»+«/mo»«msup»«msub»«mi»x«/mi»«mn»4«/mn»«/msub»«msup»«mn»2«/mn»«mo»§#160;«/mo»«/msup»«/msup»«/math» este {#5}

b) Valoarea expresiei «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mn»1«/mn»«msub»«mi»x«/mi»«mn»1«/mn»«/msub»«/mfrac»«mo»+«/mo»«mfrac»«mn»1«/mn»«msub»«mi»x«/mi»«mn»2«/mn»«/msub»«/mfrac»«mo»+«/mo»«mfrac»«mn»1«/mn»«msub»«mi»x«/mi»«mn»3«/mn»«/msub»«/mfrac»«mo»+«/mo»«mfrac»«mn»1«/mn»«msub»«mi»x«/mi»«mn»4«/mn»«/msub»«/mfrac»«/math» este {#6}.

3. Dat polinomul Q(X)=#Q, atunci:

câtul împărţirii lui P la Q este {#7}

iar restul acestei împărţiri este {#8}.

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