Reducció |
En el sistema lineal «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfenced mathcolor=¨#00007F¨ open=¨{¨ close=¨}¨»«mtable»«mtr»«mtd»«mn mathvariant=¨bold¨ mathcolor=¨#FF0000¨»4«/mn»«mi mathvariant=¨bold-italic¨»x«/mi»«mo mathvariant=¨bold¨»-«/mo»«mn mathvariant=¨bold¨»10«/mn»«mi mathvariant=¨bold-italic¨»y«/mi»«mo mathvariant=¨bold¨»=«/mo»«mn mathvariant=¨bold¨»6«/mn»«/mtd»«/mtr»«mtr»«mtd»«mo mathvariant=¨bold¨ mathcolor=¨#FF0000¨»-«/mo»«mn mathvariant=¨bold¨ mathcolor=¨#FF0000¨»6«/mn»«mi mathvariant=¨bold-italic¨»x«/mi»«mo mathvariant=¨bold¨»+«/mo»«mn mathvariant=¨bold¨»5«/mn»«mi mathvariant=¨bold-italic¨»y«/mi»«mo mathvariant=¨bold¨»=«/mo»«mo mathvariant=¨bold¨»-«/mo»«mn mathvariant=¨bold¨»19«/mn»«/mtd»«/mtr»«/mtable»«/mfenced»«/math» multiplicant la 1a per 3(12:4) i la 2a per -2(12:-6) «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfenced mathcolor=¨#00007F¨ open=¨{¨ close=¨}¨»«mtable»«mtr»«mtd»«mn mathvariant=¨bold¨ mathcolor=¨#007F00¨»12«/mn»«mi mathvariant=¨bold¨»x«/mi»«mo mathvariant=¨bold¨»-«/mo»«mn mathvariant=¨bold¨»30«/mn»«mi mathvariant=¨bold¨»y«/mi»«mo mathvariant=¨bold¨»=«/mo»«mn mathvariant=¨bold¨»18«/mn»«/mtd»«/mtr»«mtr»«mtd»«mn mathvariant=¨bold¨ mathcolor=¨#007F00¨»12«/mn»«mi mathvariant=¨bold¨»x«/mi»«mo mathvariant=¨bold¨»-«/mo»«mn mathvariant=¨bold¨»10«/mn»«mi mathvariant=¨bold¨»y«/mi»«mo mathvariant=¨bold¨»=«/mo»«mn mathvariant=¨bold¨»38«/mn»«/mtd»«/mtr»«/mtable»«/mfenced»«mo»§#160;«/mo»«/math» REST0 la 2a de la 1a i ens queda: -20y = -20, o sigui y = 1. Elimino la y per trobar la x, o substitueixo. Solució: (4,1) |