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 <question type="category"><category><text>1rBTX 03. EQUACIONS I INEQUACIONS/1.3.1 Equacions de 1r grau</text></category></question>
 
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      <text>1.00.1.10DT RESOLUCIÓ FINAL</text>
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<td style="background-color: #003300; background-image: url('http://lcmates.eu/none'); color: #ffcc00; text-align: center; vertical-align: top; border-style: none; width: 400px;" valign="top"><span style="font-size: large; color: #ffff99;" data-mce-mark="1"><span style="font-size: large; color: #ffff99;" data-mce-mark="1">Resolució final</span></span></td>
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<p><span style="color: #003300; font-size: small;"><strong>Quan ja tenim un sol terme amb les incògnites a l'esquerra i un sol terme de nombres a l'esquerra, n'hi ha prou amb DIVIDIR els dos membres pel coeficient de la incògnita: </strong></span></p>
<p><strong style="color: #003300; font-size: small; text-align: left; line-height: 1.4;"><span style="font-size: medium; color: #0000ff;">6</span>x = 24</strong></p>
<p><strong style="color: #003300; font-size: small; text-align: left; line-height: 1.4;">Dividim per <span style="font-size: medium; color: #0000ff;">6</span>:</strong></p>
<p><span style="color: #003300;"><strong style="color: #003300; font-size: small; text-align: left; line-height: 1.4;">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac mathcolor=¨#003300¨»«mrow»«mn mathvariant=¨bold¨ mathcolor=¨#0000FF¨»6«/mn»«mi mathvariant=¨bold¨»x«/mi»«/mrow»«mn mathvariant=¨bold¨ mathcolor=¨#0000FF¨»6«/mn»«/mfrac»«mo mathvariant=¨bold¨ mathcolor=¨#003300¨»=«/mo»«mfrac mathcolor=¨#003300¨»«mn mathvariant=¨bold¨»24«/mn»«mn mathvariant=¨bold¨ mathcolor=¨#0000FF¨»6«/mn»«/mfrac»«mo mathvariant=¨bold¨ mathcolor=¨#003300¨»§#8660;«/mo»«mi mathvariant=¨bold¨ mathcolor=¨#003300¨»x«/mi»«mo mathvariant=¨bold¨ mathcolor=¨#003300¨»§#160;«/mo»«mo mathvariant=¨bold¨ mathcolor=¨#003300¨»=«/mo»«mo mathvariant=¨bold¨ mathcolor=¨#003300¨»§#160;«/mo»«mn mathvariant=¨bold¨ mathcolor=¨#003300¨»4«/mn»«/math»</strong></span></p>
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