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<font size="4" style="font-family: times new roman,times,serif; font-style: italic;">El dominio de la función <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»#f1«/mi»«mfenced»«mi»#x1«/mi»«/mfenced»«mo»=«/mo»«mfrac»«mrow»«mi»#a2«/mi»«mi»#x1«/mi»«mi»#s1«/mi»«mi»#a1«/mi»«/mrow»«mrow»«mi»#a3«/mi»«msqrt»«mrow»«mi»#a1«/mi»«mi»#x1«/mi»«mi»#s1«/mi»«mi»#a2«/mi»«/mrow»«/msqrt»«/mrow»«/mfrac»«mi»#s1«/mi»«mi»#a4«/mi»«/math»</span> está representado p<font size="4">or el intervalo:</font><br /> </font><br />
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<font size="4" style="font-style: italic;"><span style="font-family: times new roman,times,serif;"> Solución:</span><br style="font-family: times new roman,times,serif;" /><br style="font-family: times new roman,times,serif;" /><span style="font-family: times new roman,times,serif;">Para determinar el dominio hay que aplicar restricciones, en este caso la raíz<font size="4"> tiene restricción y el de<font size="4">nominador algebraico también</font></font><font size="4">. Como <font size="4">el ar<font size="4">gumento de u<font size="4">na raíz con radical par no puede ser negativo,</font></font></font></font></span></font> <i><font face="times new roman,times,serif" size="4">la restricción es:</font></i><br /> <div align="center"><font size="4" style="font-style: italic;"><span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#a1«/mi»«mi»#x1«/mi»«mi»#s1«/mi»«mi»#a2«/mi»«mo»§#10878;«/mo»«mn»0«/mn»«/math»</span><span style="font-family: times new roman,times,serif;"></span></font><br /><font size="4"><i><font face="times new roman,times,serif"><br /></font></i></font> <div align="left"><font size="4"><i><font face="times new roman,times,serif">Además, como la expresión <span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«msqrt»«mrow»«mi»#a1«/mi»«mi»#x1«/mi»«mi»#s1«/mi»«mi»#a2«/mi»«/mrow»«/msqrt»«/math»</span> está en el denominador, agregamos la restricción <span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«msqrt»«mrow»«mi»#a1«/mi»«mi»#x1«/mi»«mi»#s1«/mi»«mi»#a2«/mi»«/mrow»«/msqrt»«mo»§#8800;«/mo»«mn»0«/mn»«/math»</span>. Si observamos que esta última es equivalente a </font></i></font><font size="4" style="font-style: italic;"><font size="4"><font size="4"><font size="4"><font size="4"><font size="4" style="font-style: italic;"><font size="4"><font face="times new roman,times,serif"><span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#a1«/mi»«mi»#x1«/mi»«mi»#s1«/mi»«mi»#a2«/mi»«mo»§#8800;«/mo»«mn»0«/mn»«/math»</span>, las restricciones las podemos juntar en una s</font><font face="times new roman,times,serif" size="4">ola inecuación:</font><br /></font></font></font></font></font></font></font> <div align="center"><font size="4" style="font-style: italic;"><font size="4"><font size="4"><font size="4"><font size="4"><font size="4" style="font-style: italic;"><span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#a1«/mi»«mi»#x1«/mi»«mi»#s1«/mi»«mi»#a2«/mi»«mo»§gt;«/mo»«mn»0«/mn»«/math»</span></font></font></font></font></font></font></div></div><font size="4" style="font-style: italic;"><span style="font-family: times new roman,times,serif;"></span></font></div><font size="4" style="font-style: italic;"><span style="font-family: times new roman,times,serif;">para resolverla realizamos lo siguiente:<br /><br style="font-family: times new roman,times,serif;" /></span></font> <div align="center"><font size="4" style="font-style: italic;"><span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mtable»«mtr»«mtd»«mi»#a1«/mi»«mi»#x1«/mi»«mi»#s1«/mi»«mi»#a2«/mi»«/mtd»«mtd»«mi»#D1«/mi»«/mtd»«mtd»«mn»0«/mn»«/mtd»«mtd»«mo»/«/mo»«mo»§nbsp;«/mo»«/mtd»«mtd»«mi»#s2«/mi»«mi»#a2«/mi»«mo»§nbsp;«/mo»«/mtd»«mtd»«mo»§nbsp;«/mo»«/mtd»«/mtr»«mtr»«mtd»«mi»#a1«/mi»«mi»#x1«/mi»«/mtd»«mtd»«mi»#D1«/mi»«/mtd»«mtd»«mi»#w2«/mi»«/mtd»«mtd»«mo»/«/mo»«/mtd»«mtd»«mo»·«/mo»«mi»#s3«/mi»«mfrac»«mn»1«/mn»«mrow»«mi»#w3«/mi»«/mrow»«/mfrac»«/mtd»«mtd»«mfenced»«mrow»«mi»#t1«/mi»«/mrow»«/mfenced»«/mtd»«/mtr»«mtr»«mtd»«mi»#x1«/mi»«/mtd»«mtd»«mi»#D2«/mi»«/mtd»«mtd»«mi»#sol«/mi»«/mtd»«mtd»«mo»§nbsp;«/mo»«/mtd»«mtd»«mo»§nbsp;«/mo»«/mtd»«mtd»«mo»§nbsp;«/mo»«/mtd»«/mtr»«/mtable»«/math»</span></font><br style="font-family: times new roman,times,serif;" /></div><font size="4" style="font-style: italic;"><span style="font-family: times new roman,times,serif;">Observemos que el conjunto solución consiste en todos los números #x1 #t2 </span><span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#sol«/mi»«/math»</span><span style="font-family: times new roman,times,serif;">. P<font size="4">or lo tanto, el dominio está re<font size="4">presentado por el c<font size="4">onjunto:</font></font></font></span></font><br /> <div style="text-align: center; font-family: times new roman,times,serif;"><font size="4">#opa</font></div>
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a., b., c., ...
A., B., C., ...
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i., ii., iii., ...
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No numbering
WIRIS variables
Algorithm
Choice 1
Answer
#opa
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<font size="4"><span style="font-family: times new roman,times,serif; font-style: italic;">Bien. Continúa de esta manera.</span></font>
Choice 2
Answer
#opb
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<font size="4" style="font-family: times new roman,times,serif; font-style: italic;">Observa que hay elementos de <span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#opb«/mi»«/math»</span> que no pueden ser evaluados en <span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#f1«/mi»«/math»</span>. Revisa tu desarrollo.</font>
Choice 3
Answer
#opc
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<font size="4" style="font-family: times new roman,times,serif; font-style: italic;"><font size="4" style="font-family: times new roman,times,serif; font-style: italic;">Observa que hay elementos de </font></font><font size="4" style="font-family: times new roman,times,serif; font-style: italic;"><font size="4" style="font-family: times new roman,times,serif; font-style: italic;"><font size="4" style="font-family: times new roman,times,serif; font-style: italic;"><span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#opc«/mi»«/math»</span></font> que no pueden ser evaluados en <span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#f1«/mi»«/math»</span>. Revisa tu desarrollo.</font></font>
Choice 4
Answer
#opd
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<font size="4" style="font-family: times new roman,times,serif; font-style: italic;"><font size="4" style="font-family: times new roman,times,serif; font-style: italic;"><font size="4" style="font-family: times new roman,times,serif; font-style: italic;">Observa que hay elementos de </font></font></font><font size="4" style="font-family: times new roman,times,serif; font-style: italic;"><font size="4" style="font-family: times new roman,times,serif; font-style: italic;"><font size="4" style="font-family: times new roman,times,serif; font-style: italic;"><font size="4" style="font-family: times new roman,times,serif; font-style: italic;"><span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#opd«/mi»«/math»</span></font> que no pueden ser evaluados en <span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#f1«/mi»«/math»</span>. Revisa tu desarrollo.</font></font></font>
Choice 5
Answer
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Choice 6
Answer
Grade
None
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Choice 7
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None
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Feedback
Combined feedback
For any correct response
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Options
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For any incorrect response
Settings for multiple tries
Penalty for each incorrect try
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Hint 1
Hint text
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Clear incorrect responses
Show the number of correct responses
Hint 2
Hint text
Options
Clear incorrect responses
Show the number of correct responses
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Created
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Admin User
on
Tuesday, 13 August 2013, 4:22 PM
Last saved
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Admin User
on
Tuesday, 13 August 2013, 4:22 PM
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