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<font face="'times new roman', times, serif" size="4"><i>Al factorizar al máximo la expresión <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»#N1«/mi»«mi»#L1«/mi»«mi»#J1«/mi»«mi»#s1«/mi»«mi»#N2«/mi»«mi»#L2«/mi»«mi»#J2«/mi»«mi»#s2«/mi»«mi»#N3«/mi»«mi»#L3«/mi»«mi»#J3«/mi»«/math»</span> da como resultado:</i></font>
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<font size="4" style="font-style: italic;"><span style="font-family: times new roman,times,serif;"> Solución: </span></font> <div style="font-family: times new roman,times,serif; font-style: italic;"><font size="4"><br /></font></div> <div style="font-family: times new roman,times,serif; font-style: italic;"><font size="4">Para factorizar al máximo la expresión </font><font face="'times new roman', times, serif" size="4"><i><span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#N1«/mi»«mi»#L1«/mi»«mi»#J1«/mi»«mi»#s1«/mi»«mi»#N2«/mi»«mi»#L2«/mi»«mi»#J2«/mi»«mi»#s2«/mi»«mi»#N3«/mi»«mi»#L3«/mi»«mi»#J3«/mi»«/math»</span></i></font><font size="4"> tenemos que determinar cuál es el factor común entre cada uno de los términos, identificando los factores comunes entre los coeficientes y cada término literal:</font></div> <div style="font-family: times new roman,times,serif; font-style: italic;"><font size="4"><br />El factor común entre los coeficientes encerrados </font></div> <div style="font-family: times new roman,times,serif; font-style: italic;"><font size="4"><span style="font-size: large;"><span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«menclose notation="box"»«mi»#N1«/mi»«/menclose»«mi»#L1«/mi»«mi»#J1«/mi»«mi»#s1«/mi»«menclose notation="box"»«mrow»«mi»#N2«/mi»«/mrow»«/menclose»«mi»#L2«/mi»«mi»#J2«/mi»«mi»#s2«/mi»«menclose notation="box"»«mrow»«mi»#N3«/mi»«/mrow»«/menclose»«mi»#L3«/mi»«mi»#J3«/mi»«/math»</span> es: <span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#m1«/mi»«/math»</span> <br />El factor entre las potencias de #V1 </span><span style="font-size: large;">(las que están </span><span style="font-size: large;">encerradas)</span></font><font size="4"><br /><span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#N1«/mi»«menclose notation="box"»«mi»#L1«/mi»«/menclose»«mi»#J1«/mi»«mi»#s1«/mi»«mi»#N2«/mi»«menclose notation="box"»«mrow»«mi»#L2«/mi»«/mrow»«/menclose»«mi»#J2«/mi»«mi»#s2«/mi»«mi»#N3«/mi»«menclose notation="box"»«mrow»«mi»#L3«/mi»«/mrow»«/menclose»«mi»#J3«/mi»«/math»</span> es #l1<br /><span style="font-size: large;"></span></font><font size="4"><span style="font-size: large;"><br />El factor entre las potencias de #V2 </span><span style="font-size: large;">(las que están </span><span style="font-size: large;">encerradas)<br /></span></font><font size="4"><span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#N1«/mi»«mi»#L1«/mi»«menclose notation="box"»«mi»#J1«/mi»«/menclose»«mi»#s1«/mi»«mi»#N2«/mi»«mi»#L2«/mi»«menclose notation="box"»«mrow»«mi»#J2«/mi»«/mrow»«/menclose»«mi»#s2«/mi»«mi»#N3«/mi»«mi»#L3«/mi»«menclose notation="box"»«mrow»«mi»#J3«/mi»«/mrow»«/menclose»«/math»</span></font><font size="4"> es: #j1<br /><br />Por lo tanto, el factor común máximo del trinomio es la multiplicación de los tres términos obtenidos más arriba: <span style="font-size: large;"><span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#m2«/mi»«/math»</span></span>#l1#j1. <br />Luego, si factorizamos </font><font face="'times new roman', times, serif" size="4"><i><span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#N1«/mi»«mi»#L1«/mi»«mi»#J1«/mi»«mi»#s1«/mi»«mi»#N2«/mi»«mi»#L2«/mi»«mi»#J2«/mi»«mi»#s2«/mi»«mi»#N3«/mi»«mi»#L3«/mi»«mi»#J3«/mi»«/math»</span></i></font><font size="4"> por </font><font size="4"><span style="font-size: large;"><span class="nolink">«math xmlns="http://www.w3.org/1998/Math/MathML"»«mi»#m2«/mi»«mi»#l1«/mi»«mi»#j1«/mi»«/math»</span></span></font><font size="4"> nos queda: <br /></font> <div style="text-align: center;"><font size="4">#opa</font><br /></div><font size="4"><br /></font><font size="4">Para corroborar, puedes desarrollar la multiplicación y obtener el trinomio original.<br /><br /></font></div>
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Choice 1
Answer
#opa
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<i><font face="'times new roman', times, serif" size="4">¡Excelente!</font></i>
Choice 2
Answer
#opb
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<font face="'times new roman', times, serif" size="4"><i>Revisa los signos y observa que al desarrollar la expresión no obtienes la original.</i></font>
Choice 3
Answer
#opc
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<font face="'times new roman', times, serif" size="4"><i>Factorizaste, pero no al máximo. La expresión #exp1 aún se puede seguir factorizando.</i></font>
Choice 4
Answer
#opd
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<i>Factorizaste, pero no al máximo. La expresión #exp2 aún se puede seguir factorizando.</i>
Choice 5
Answer
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Choice 6
Answer
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Choice 7
Answer
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Tuesday, 13 August 2013, 4:22 PM
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