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<p>Donada la funció del gràfic #Dibuix, estudiem el límit en el punt: x=#x_1</p> <p><span style="line-height: 1.4;">Si x= #x_1</span></p> <p style="padding-left: 30px;"><span style="line-height: 1.4;"> </span>«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«munder»«mi»lim«/mi»«mrow»«mi»x«/mi»«mo»§#8594;«/mo»«mo»#«/mo»«mi»x«/mi»«mo»_«/mo»«msup»«mn»1«/mn»«mo»-«/mo»«/msup»«/mrow»«/munder»«mi»f«/mi»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«mo»§#160;«/mo»«mo»=«/mo»«munder»«mi»lim«/mi»«mrow»«mi»x«/mi»«mo»§#8594;«/mo»«mo»#«/mo»«mi»x«/mi»«mo»_«/mo»«msup»«mn»1«/mn»«mo»-«/mo»«/msup»«/mrow»«/munder»«mfenced»«mrow»«mo»#«/mo»«mi»f«/mi»«mi»p«/mi»«/mrow»«/mfenced»«mo»=«/mo»«/math» {:MC:=\#le1~\#le2~\#le3~\#le4}</p> <p style="padding-left: 30px;"><span> </span>«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«munder»«mi»lim«/mi»«mrow»«mi»x«/mi»«mo»§#8594;«/mo»«mo»#«/mo»«mi»x«/mi»«mo»_«/mo»«msup»«mn»1«/mn»«mo»+«/mo»«/msup»«/mrow»«/munder»«mi»f«/mi»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«mo»§#160;«/mo»«mo»=«/mo»«munder»«mi»lim«/mi»«mrow»«mi»x«/mi»«mo»§#8594;«/mo»«mo»#«/mo»«mi»x«/mi»«mo»_«/mo»«msup»«mn»1«/mn»«mo»+«/mo»«/msup»«/mrow»«/munder»«mfenced»«mrow»«mo»#«/mo»«mi»f«/mi»«mi»s«/mi»«/mrow»«/mfenced»«mo»=«/mo»«/math» {:MC:=\#ld1~\#ld2~\#ld3~\#ld4}</p> <p style="padding-left: 30px;"><span style="line-height: 1.4;"><span style="line-height: 1.4;">I, per tant, «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«munder»«mi»lim«/mi»«mrow»«mi»x«/mi»«mo»§#8594;«/mo»«mo»#«/mo»«mi»x«/mi»«mo»_«/mo»«mn»1«/mn»«/mrow»«/munder»«mi»f«/mi»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«mo»§#160;«/mo»«mo»=«/mo»«/math»{:MC:=\#e1~\#e2~\#e3~\#e4}</span></span></p>
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Monday, 12 August 2013, 9:03 AM
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