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<p><span style="color: #006600;"><span style="font-weight: bold; color: #003300;">Considera la funció f(x) = #f_5. </span><br style="font-weight: bold;" /><span style="color: #003300;"><span style="font-weight: bold;">Troba l'equació de la recta tangent al gràfic de f(x) en el punt d'abscissa x</span><sub style="font-weight: bold;">0</sub><span style="font-weight: bold;"> = #x_0.</span></span><br style="font-weight: bold;" /><br style="font-weight: bold;" /><span style="font-weight: bold; color: #003300;">Calcula primer f(#x_0) = {1:SHORTANSWER: ~=#f_0}</span><br style="font-weight: bold;" /><span style="color: #003300;"><span style="font-weight: bold;">Deriva f(x): f'(x)= {1:SHORTANSWER: ~=#f_1}</span> Format de la resposta : -3*x/(2*x^2-12*x+9)</span><br style="font-weight: bold;" /><span style="font-weight: bold; color: #003300;">Calcula f'(#x_0)= {1:SHORTANSWER: ~=#f_2} </span><br style="font-weight: bold;" /><span style="color: #003300;"><span style="font-weight: bold;">L'equació de la recta tangent es calcula doncs amb:</span> <span style="font-weight: bold;"><br />y - {1:SHORTANSWER: ~=#f_0} = {1:SHORTANSWER: ~=#f_2}·(x - {1:SHORTANSWER: ~=#x_0})</span></span><br /><br /><span style="color: #003300;"><span style="font-weight: bold;">En forma explícita l'equació és: </span><span style="font-weight: bold;">{1:SHORTANSWER: ~=#e_1}</span></span><br /><br /><br /><br /><br style="font-weight: bold;" /></span></p>
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Thursday, 23 August 2018, 4:18 PM
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