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<table style="border: 4px solid #003300; float: none; text-align: left; vertical-align: top; color: #003300; width: 400px; background-image: url('http://www.insmilaifontanals.cat/none'); background-color: #ffffcc;" border="4" frame="void" rules="none" align="center"> <tbody> <tr align="center"> <td style="background-color: #003300; background-image: none; color: #ffcc00; border-color: #000066; border-width: 4px; vertical-align: top; border-style: none; text-align: center;" valign="top" width="100%"><span style="font-size: large; color: #ffff99;">Resolució de sistemes no lineals</span></td> </tr> <tr> <td style="background-color: #ffffcc; background-image: none; color: #003300; border-color: #000066; border-width: 4px; text-align: left; vertical-align: top; border-style: none;" valign="top" width="100%"><strong><span style="font-size: small; color: #003300;">Un sistema no lineal es resol per <span style="text-decoration: underline;">substitució</span>.</span></strong><br style="font-weight: bold;" /><span style="color: #003300;"><strong><span style="font-size: small;">Exemple:</span></strong></span><br /><span style="color: #003300;"><strong><span style="font-size: small;">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mstyle mathsize=¨14px¨»«mfenced mathcolor=¨#003300¨ open=¨{¨ close=¨¨»«mtable»«mtr»«mtd»«mi mathvariant=¨bold¨»x«/mi»«mo mathvariant=¨bold¨»+«/mo»«mi mathvariant=¨bold¨»y«/mi»«mo mathvariant=¨bold¨»=«/mo»«mn mathvariant=¨bold¨»6«/mn»«/mtd»«/mtr»«mtr»«mtd»«msup»«mi mathvariant=¨bold¨»x«/mi»«mn mathvariant=¨bold¨»2«/mn»«/msup»«mo mathvariant=¨bold¨»+«/mo»«msup»«mi mathvariant=¨bold¨»y«/mi»«mn mathvariant=¨bold¨»2«/mn»«/msup»«mo mathvariant=¨bold¨»=«/mo»«mn mathvariant=¨bold¨»20«/mn»«/mtd»«/mtr»«/mtable»«/mfenced»«/mstyle»«/math»</span></strong></span><br style="font-weight: bold;" /><strong><span style="font-size: small; color: #003300;">Aïllo y en la primera equació: y = <span style="color: #ff0000;">6 - x</span></span></strong><br style="font-weight: bold;" /><span style="color: #003300;"><strong><span style="font-size: small;">Substitueixo en la segona equació: x<sup style="font-weight: bold;">2</sup> + (<span style="color: #ff0000;">6-x</span>)<sup style="font-weight: bold;">2</sup> = 20 i resolc el 2n grau: 2x<sup>2</sup> - 12x + 16 = 0.</span></strong></span><br /><strong><span style="font-size: small; color: #003300;">Solucions: (2,4) i (4,2)</span></strong></td> </tr> </tbody> </table>
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