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<p><span style="font-weight: bold; color: #003300;">Factoritza el polinomi P(x) = «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mstyle mathsize=¨12px¨»«mrow»«mo mathvariant=¨bold¨ mathcolor=¨#003300¨»#«/mo»«mi mathvariant=¨bold¨ mathcolor=¨#003300¨»P«/mi»«mo»§#160;«/mo»«/mrow»«/mstyle»«/math»</span><br style="font-weight: bold;" /><br style="font-weight: bold;" /><span style="font-weight: bold; color: #003300;"><span style="color: #ff6600;">Format de la resposta:</span> </span>(x+2)·(x-1)·(2x<sup>2</sup>+4x+9)</p>
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Answer 1
Answer
Grade
None
100%
90%
83.33333%
80%
75%
70%
66.66667%
60%
50%
40%
33.33333%
30%
25%
20%
16.66667%
14.28571%
12.5%
11.11111%
10%
5%
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Answer 2
Answer
Grade
None
100%
90%
83.33333%
80%
75%
70%
66.66667%
60%
50%
40%
33.33333%
30%
25%
20%
16.66667%
14.28571%
12.5%
11.11111%
10%
5%
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Penalty for each incorrect try
100%
50%
33.33333%
25%
20%
10%
0%
Hint 1
Hint text
<p style="text-align: justify;"><strong style="color: #000066; line-height: 1.4;">Com que el polinomi és de grau superior a 2 i té terme independent, #c0, cal emprar el mètode de Ruffini amb tots els divisors de #c0 que són: «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo mathvariant=¨bold¨ mathcolor=¨#000066¨»§#177;«/mo»«mo mathvariant=¨bold¨ mathcolor=¨#000066¨»#«/mo»«mi mathvariant=¨bold¨ mathcolor=¨#000066¨»t«/mi»«/math».</strong></p> <p><strong>El primer divisor és #t1:</strong></p> <table style="border-color: #ff6600; border-width: 2px; background-color: #ffffcc;" border="2"> <tbody> <tr> <td style="border: 1px solid #ff9900;"> </td> <td style="border: 1px solid #ff9900;">#c4</td> <td style="border: 1px solid #ff9900;">#c3</td> <td style="border: 1px solid #ff9900;">#c2</td> <td style="border: 1px solid #ff9900;">#c1</td> <td style="border: 1px solid #ff9900;">#c0</td> </tr> <tr> <td style="border: 1px solid #ff9900;">#f1</td> <td style="border: 1px solid #ff9900;"> </td> <td style="border: 1px solid #ff9900;"> </td> <td style="border: 1px solid #ff9900;"> </td> <td style="border: 1px solid #ff9900;"> </td> <td style="border: 1px solid #ff9900;"> </td> </tr> <tr> <td style="border: 1px solid #ff9900;"> </td> <td style="border: 1px solid #ff9900;"> </td> <td style="border: 1px solid #ff9900;"> </td> <td style="border: 1px solid #ff9900;"> </td> <td style="border: 1px solid #ff9900;"> </td> <td style="border: 1px solid #ff9900;"> </td> </tr> </tbody> </table>
Hint 2
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<p><strong><span style="color: #000066;">El resultat de la primera divisió per #t1 ens dona de quocient #Q1. Com que el grau és superior a 2, i té terme independent, #g2, cal emprar el mètode de Ruffini amb tots els divisors de #g0, que són «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo mathvariant=¨bold¨ mathcolor=¨#000066¨»§#177;«/mo»«mo mathvariant=¨bold¨ mathcolor=¨#000066¨»§#160;«/mo»«mo mathvariant=¨bold¨ mathcolor=¨#000066¨»#«/mo»«mi mathvariant=¨bold¨ mathcolor=¨#000066¨»u«/mi»«/math».</span></strong></p> <p><strong><span style="color: #000066;">El segon divisor és #t2:</span></strong></p> <table style="border-color: #ff6600; border-width: 2px; background-color: #ffffcc;" border="2"> <tbody> <tr> <td style="border: 1px solid #ff9900;"> </td> <td style="border: 1px solid #ff9900;">#c4</td> <td style="border: 1px solid #ff9900;">#c3</td> <td style="border: 1px solid #ff9900;">#c2</td> <td style="border: 1px solid #ff9900;">#c1</td> <td style="border: 1px solid #ff9900;">#c0</td> </tr> <tr> <td style="border: 1px solid #ff9900;">#f1</td> <td style="border: 1px solid #ff9900;"> </td> <td style="border: 1px solid #ff9900;"> #h3</td> <td style="border: 1px solid #ff9900;">#h2 </td> <td style="border: 1px solid #ff9900;">#h1 </td> <td style="border: 1px solid #ff9900;"> #h0</td> </tr> <tr> <td style="border: 1px solid #ff9900;"> </td> <td style="border: 1px solid #ff9900;"> #g3</td> <td style="border: 1px solid #ff9900;">#g2</td> <td style="border: 1px solid #ff9900;">#g1 </td> <td style="border: 1px solid #ff9900;">#g0 </td> <td style="border: 1px solid #ff9900;"> 0</td> </tr> <tr> <td style="border: 1px solid #ff9900;">#f2</td> <td style="border: 1px solid #ff9900;"> </td> <td style="border: 1px solid #ff9900;"> </td> <td style="border: 1px solid #ff9900;"> </td> <td style="border: 1px solid #ff9900;"> </td> <td style="border: 1px solid #ff9900;"> </td> </tr> </tbody> </table> <p><span style="color: #0000ff;"><strong>Ara cal resoldre, si es pot, l'equació de 2n grau.</strong></span></p>
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Thursday, 23 August 2018, 11:08 AM
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