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<p><em>Se han derramado <span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»#v«/mi»«/math»</span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span> <span class="nolink"><span class="nolink"></span></span>de </span>petróleo en el mar, dejando una mancha con forma de cilindro recto circular. <br></em></p> <p><em>Calcula la rapidez con que aumenta el radio de la mancha si el espesor disminuye a razón de <span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"></span></span></span></span></span></span></span><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»#h«/mi»«mo»/«/mo»«mi»#ut«/mi»«/math»</span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span> en el instante en que su radio es de <span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»#r«/mi»«/math»<br></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></em></p><p><em><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><br></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></em></p><p><em><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">obs: Considere que el volumen de la mancha no cambia (permanece constante)</span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span><span class="nolink"><span class="nolink"></span></span></span></em></p> <p><em><span class="nolink"></span></em></p>
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<p></p> <p align="justify"><em>Solución:</em></p> <p align="justify"><em>Para resolver el ejercicio, debemos hallar la velocidad con que aumenta el radio <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»R«/mi»«/math»</span> a medida que la mancha se expande sobre la superficie del mar en el instante en que <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»R«/mi»«mo»=«/mo»«mi»#r«/mi»«/math»</span>.</em></p> <p align="justify"><em>Sabemos que el volumen de la mancha permanece constante y que está en función del radio <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»R«/mi»«/math»</span> y de la altura <span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»h«/mi»«/math»</span></span></span></span>, los que varían respecto al tiempo.</em></p> <p align="justify"><em>Como la mancha es de forma cilíndrica, su volumen está dado por:</em></p> <p align="justify"><span class="nolink"><em><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»V«/mi»«mo»=«/mo»«mi»§#960;«/mi»«msup»«mi»R«/mi»«mn»2«/mn»«/msup»«mi»h«/mi»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»,«/mo»«mo»§nbsp;«/mo»«mo»§#8704;«/mo»«mi»t«/mi»«mo»§#8805;«/mo»«mn»0«/mn»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»(«/mo»«mn»1«/mn»«mo»)«/mo»«/math»</span></span></span></span></span></span></span></span></span></em></span></p> <p align="justify"><em>Derivamos ambos miembros de la igualdad respecto a <span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»t«/mi»«/math»</span></span></span></span></span></span></span></span></span></span>:</em></p> <p align="justify"><span class="nolink"><em><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mi»d«/mi»«mi»V«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»t«/mi»«/mrow»«/mfrac»«mo»=«/mo»«mi»§#960;«/mi»«mfenced»«mrow»«mn»2«/mn»«mi»R«/mi»«mo»·«/mo»«mfrac»«mrow»«mi»d«/mi»«mi»R«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»t«/mi»«/mrow»«/mfrac»«mo»·«/mo»«mi»h«/mi»«mo»+«/mo»«msup»«mi»R«/mi»«mn»2«/mn»«/msup»«mo»·«/mo»«mfrac»«mrow»«mi»d«/mi»«mi»h«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»t«/mi»«/mrow»«/mfrac»«/mrow»«/mfenced»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»(«/mo»«mn»2«/mn»«mo»)«/mo»«/math»</span></span></span></span></span></span></span></span></span></em></span></p> <p align="justify"><em>Como el volumen <span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»V«/mi»«/math»</span></span></span></span> es constante (independiente del tiempo) <span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mi»d«/mi»«mi»V«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»t«/mi»«/mrow»«/mfrac»«mo»=«/mo»«mn»0«/mn»«/math»</span></span></span></span></span></span></span></span></span></span>.<br></em></p> <p align="justify"><em>Por lo tanto, de la igualdad anterior obtenemos:</em></p> <p align="justify"><span class="nolink"><em><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mn»0«/mn»«mo»=«/mo»«mn»2«/mn»«mi»R«/mi»«mo»·«/mo»«mfrac»«mrow»«mi»d«/mi»«mi»R«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»t«/mi»«/mrow»«/mfrac»«mo»·«/mo»«mi»h«/mi»«mo»+«/mo»«msup»«mi»R«/mi»«mn»2«/mn»«/msup»«mo»·«/mo»«mfrac»«mrow»«mi»d«/mi»«mi»h«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»t«/mi»«/mrow»«/mfrac»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«/math»</span></span></span></span></span></span></span></span></span></em></span></p> <p align="justify"><em>Despejando <span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mi»d«/mi»«mi»R«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»t«/mi»«/mrow»«/mfrac»«/math»</span></span></span></span></span></span></span></span></span></span> obtenemos:</em></p> <p align="justify"><span class="nolink"><em><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mi»d«/mi»«mi»R«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»t«/mi»«/mrow»«/mfrac»«mo»=«/mo»«mfrac»«mrow»«mo»-«/mo»«mi»R«/mi»«/mrow»«mrow»«mn»2«/mn»«mi»h«/mi»«/mrow»«/mfrac»«mo»·«/mo»«mfrac»«mrow»«mi»d«/mi»«mi»h«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»t«/mi»«/mrow»«/mfrac»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»(«/mo»«mn»3«/mn»«mo»)«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«/math»</span></span></span></span></span></span></span></span></span></em></span></p> <p align="justify"><span class="nolink"><em>Los datos que tenemos son los siguientes:<span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»V«/mi»«mo»=«/mo»«mi»#v«/mi»«/math»</span></span></span></span></span></span></span></span></span> <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»R«/mi»«mo»=«/mo»«mi»#r«/mi»«/math»</span> y <span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mi»d«/mi»«mi»h«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»t«/mi»«/mrow»«/mfrac»«mo»=«/mo»«mo»-«/mo»«mi»#h«/mi»«mo»/«/mo»«mi»#ut«/mi»«/math»</span></span></span></span></span></span></span></span></span> (este valor es negativo ya que el espesor de la mancha "disminuye" a razón de <span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»#h«/mi»«mo»/«/mo»«mi»#ut«/mi»«/math»</span></span></span></span></span></span></span></span></span>)</em></span></p> <p align="justify"><span class="nolink"><em>De la relación <span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»(«/mo»«mn»1«/mn»«mo»)«/mo»«/math»</span></span></span></span></span></span></span></span></span> despejamos <span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»h«/mi»«/math»</span></span></span>:</em></span></p> <p align="justify"><span class="nolink"><em><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»h«/mi»«mo»=«/mo»«mfrac»«mi»V«/mi»«mrow»«mi»§#960;«/mi»«msup»«mi»R«/mi»«mn»2«/mn»«/msup»«/mrow»«/mfrac»«/math»</span></span></span></span></span></span></span></span></span></em></span></p> <p align="justify"><span class="nolink"><em>Debemos trabajar en las mismas unidades de medida, por lo tanto, como el volumen <span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»V«/mi»«/math»</span></span></span>está en #u3, escribiremos el radio <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»R«/mi»«/math»</span> en #u4.</em></span></p> <p align="justify"><span class="nolink"><em>Por lo tanto, <span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»R«/mi»«mo»=«/mo»«mi»#r«/mi»«mo»=«/mo»«mi»#c3«/mi»«/math»</span></span></span></span></span></span></span></span></span></em></span></p> <p align="justify"><em><span class="nolink">Reemplazando en </span><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»h«/mi»«mo»=«/mo»«mfrac»«mi»V«/mi»«mrow»«mi»§#960;«/mi»«msup»«mi»R«/mi»«mn»2«/mn»«/msup»«/mrow»«/mfrac»«mo»=«/mo»«mfrac»«mi»#v«/mi»«mrow»«mi»§#960;«/mi»«mo»·«/mo»«msup»«mfenced»«mi»#c3«/mi»«/mfenced»«mn»2«/mn»«/msup»«/mrow»«/mfrac»«mo»=«/mo»«mi»#h1«/mi»«/math»</span></span></span></span></span></span></span></span></span></em></p> <p align="justify"><em>Finalmente, sustituimos los valores en <span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»(«/mo»«mn»3«/mn»«mo»)«/mo»«/math»</span></span></span></span></span></span></span></span></span>:</em></p> <p align="justify"><em><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mtable columnalign=¨left¨ rowspacing=¨0¨»«mtr»«mtd»«mfrac»«mrow»«mi»d«/mi»«mi»R«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»t«/mi»«/mrow»«/mfrac»«mo»=«/mo»«mfrac»«mrow»«mo»-«/mo»«mi»R«/mi»«/mrow»«mrow»«mn»2«/mn»«mi»h«/mi»«/mrow»«/mfrac»«mo»·«/mo»«mfrac»«mrow»«mi»d«/mi»«mi»h«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»t«/mi»«/mrow»«/mfrac»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«/mtd»«/mtr»«mtr»«mtd»«mfrac»«mrow»«mi»d«/mi»«mi»R«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»t«/mi»«/mrow»«/mfrac»«mo»=«/mo»«mfrac»«mrow»«mo»-«/mo»«mi»#c3«/mi»«/mrow»«mrow»«mn»2«/mn»«mo»·«/mo»«mi»#h1«/mi»«/mrow»«/mfrac»«mo»·«/mo»«mo»-«/mo»«mi»#h«/mi»«mo»/«/mo»«mi»#ut«/mi»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»=«/mo»«mi»#sol3«/mi»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§#8776;«/mo»«mi»#s1«/mi»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«/mtd»«/mtr»«/mtable»«/math»</span></span></span></span></span></span></span></span></span></em></p> <p align="justify"><em><span class="nolink"><span class="nolink">Por lo tanto, la velocidad con que aumenta el radio de la mancha cuando <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»R«/mi»«mo»=«/mo»«mi»#r«/mi»«/math»</span> es aproximadamente de #s1.</span></span></em></p> <p align="justify"><em></em></p>
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Number the choices?
a., b., c., ...
A., B., C., ...
1., 2., 3., ...
i., ii., iii., ...
I., II., III., ...
No numbering
WIRIS variables
Algorithm
Choice 1
Answer
#s1
Grade
None
100%
90%
83.33333%
80%
75%
70%
66.66667%
60%
50%
40%
33.33333%
30%
25%
20%
16.66667%
14.28571%
12.5%
11.11111%
10%
5%
-5%
-10%
-11.11111%
-12.5%
-14.28571%
-16.66667%
-20%
-25%
-30%
-33.33333%
-40%
-50%
-60%
-66.66667%
-70%
-75%
-80%
-83.33333%
-90%
-100%
Feedback
<p><em>¡Muy bien! Continúa de esa manera.</em></p>
Choice 2
Answer
#s2
Grade
None
100%
90%
83.33333%
80%
75%
70%
66.66667%
60%
50%
40%
33.33333%
30%
25%
20%
16.66667%
14.28571%
12.5%
11.11111%
10%
5%
-5%
-10%
-11.11111%
-12.5%
-14.28571%
-16.66667%
-20%
-25%
-30%
-33.33333%
-40%
-50%
-60%
-66.66667%
-70%
-75%
-80%
-83.33333%
-90%
-100%
Feedback
<em>Revisa el desarrollo para identificar tus errores. ¡Tú puedes!</em>
Choice 3
Answer
#s3
Grade
None
100%
90%
83.33333%
80%
75%
70%
66.66667%
60%
50%
40%
33.33333%
30%
25%
20%
16.66667%
14.28571%
12.5%
11.11111%
10%
5%
-5%
-10%
-11.11111%
-12.5%
-14.28571%
-16.66667%
-20%
-25%
-30%
-33.33333%
-40%
-50%
-60%
-66.66667%
-70%
-75%
-80%
-83.33333%
-90%
-100%
Feedback
<em>Revisa el desarrollo para identificar tus errores. ¡Tú puedes!</em>
Choice 4
Answer
#s4
Grade
None
100%
90%
83.33333%
80%
75%
70%
66.66667%
60%
50%
40%
33.33333%
30%
25%
20%
16.66667%
14.28571%
12.5%
11.11111%
10%
5%
-5%
-10%
-11.11111%
-12.5%
-14.28571%
-16.66667%
-20%
-25%
-30%
-33.33333%
-40%
-50%
-60%
-66.66667%
-70%
-75%
-80%
-83.33333%
-90%
-100%
Feedback
<em>Revisa el desarrollo para identificar tus errores. ¡Tú puedes!</em>
Choice 5
Answer
Grade
None
100%
90%
83.33333%
80%
75%
70%
66.66667%
60%
50%
40%
33.33333%
30%
25%
20%
16.66667%
14.28571%
12.5%
11.11111%
10%
5%
-5%
-10%
-11.11111%
-12.5%
-14.28571%
-16.66667%
-20%
-25%
-30%
-33.33333%
-40%
-50%
-60%
-66.66667%
-70%
-75%
-80%
-83.33333%
-90%
-100%
Feedback
Choice 6
Answer
Grade
None
100%
90%
83.33333%
80%
75%
70%
66.66667%
60%
50%
40%
33.33333%
30%
25%
20%
16.66667%
14.28571%
12.5%
11.11111%
10%
5%
-5%
-10%
-11.11111%
-12.5%
-14.28571%
-16.66667%
-20%
-25%
-30%
-33.33333%
-40%
-50%
-60%
-66.66667%
-70%
-75%
-80%
-83.33333%
-90%
-100%
Feedback
Choice 7
Answer
Grade
None
100%
90%
83.33333%
80%
75%
70%
66.66667%
60%
50%
40%
33.33333%
30%
25%
20%
16.66667%
14.28571%
12.5%
11.11111%
10%
5%
-5%
-10%
-11.11111%
-12.5%
-14.28571%
-16.66667%
-20%
-25%
-30%
-33.33333%
-40%
-50%
-60%
-66.66667%
-70%
-75%
-80%
-83.33333%
-90%
-100%
Feedback
Combined feedback
For any correct response
For any partially correct response
Options
Show the number of correct responses once the question has finished
For any incorrect response
Settings for multiple tries
Penalty for each incorrect try
100%
50%
33.33333%
25%
20%
10%
0%
Hint 1
Hint text
Options
Clear incorrect responses
Show the number of correct responses
Hint 2
Hint text
Options
Clear incorrect responses
Show the number of correct responses
Created / last saved
Created
by
Admin User
on
Wednesday, 15 February 2017, 3:41 PM
Last saved
by
Admin User
on
Wednesday, 15 February 2017, 3:41 PM
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