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Dada la funció <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»f«/mi»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«mo»=«/mo»«mi»#f«/mi»«/math»</span>, calcula el límite de esta función cuando x tiende a #a
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<!--[if !mso]> <style> v\:* {behavior:url(#default#VML);} o\:* {behavior:url(#default#VML);} w\:* {behavior:url(#default#VML);} .shape {behavior:url(#default#VML);} </style> <![endif]--><!--[if gte mso 9]><xml> <w:WordDocument> <w:View>Normal</w:View> <w:Zoom>0</w:Zoom> <w:HyphenationZone>21</w:HyphenationZone> <w:PunctuationKerning/> <w:ValidateAgainstSchemas/> <w:SaveIfXMLInvalid>false</w:SaveIfXMLInvalid> <w:IgnoreMixedContent>false</w:IgnoreMixedContent> <w:AlwaysShowPlaceholderText>false</w:AlwaysShowPlaceholderText> <w:Compatibility> <w:BreakWrappedTables/> <w:SnapToGridInCell/> <w:WrapTextWithPunct/> <w:UseAsianBreakRules/> <w:DontGrowAutofit/> </w:Compatibility> <w:BrowserLevel>MicrosoftInternetExplorer4</w:BrowserLevel> </w:WordDocument> </xml><![endif]--><!--[if gte mso 9]><xml> <w:LatentStyles DefLockedState="false" LatentStyleCount="156"> </w:LatentStyles> </xml><![endif]--><!--[if gte mso 10]> <style> /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Tabla normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Times New Roman"; mso-ansi-language:#0400; mso-fareast-language:#0400; mso-bidi-language:#0400;} </style> <![endif]--> <p class="MsoNormal"><span lang="CA">Esta función es el cociente de dos funciones, por tanto, su límite en un punto es igual al cociente de los límites de estas funciones en el punto (siempre que el denominador no sea 0). Es decir, <br /> <br /> Si <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«munder»«mo largeop=¨true¨»lim«/mo»«mrow»«mi»x«/mi»«mo»§#8594;«/mo»«mi»a«/mi»«/mrow»«/munder»«mi»g«/mi»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«mo»=«/mo»«mi»b«/mi»«/math»</span> y </span><span lang="CA"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«munder»«mo largeop=¨true¨»lim«/mo»«mrow»«mi»x«/mi»«mo»§#8594;«/mo»«mi»a«/mi»«/mrow»«/munder»«mi»h«/mi»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«mo»=«/mo»«mi»c«/mi»«/math»</span></span><span lang="CA"> entonces </span><span lang="CA"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«munder»«mo largeop=¨true¨»lim«/mo»«mrow»«mi»x«/mi»«mo»§#8594;«/mo»«mi»a«/mi»«/mrow»«/munder»«mfrac»«mrow»«mi»g«/mi»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«/mrow»«mrow»«mi»h«/mi»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«/mrow»«/mfrac»«mo»=«/mo»«mfrac»«mi»b«/mi»«mi»c«/mi»«/mfrac»«/math»</span></span><br /><span lang="CA"> Si el límite del denominador es 0, entonces el límite es infinito y se deben calular los límites laterales para establecer el signo.</span></p>
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Answer 1
Answer
Grade
None
100%
90%
83.33333%
80%
75%
70%
66.66667%
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33.33333%
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16.66667%
14.28571%
12.5%
11.11111%
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5%
Feedback
Muy bien.<br />
Answer 2
Answer
Grade
None
100%
90%
83.33333%
80%
75%
70%
66.66667%
60%
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33.33333%
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16.66667%
14.28571%
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11.11111%
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Feedback
Revisa el signo de infinito.
Answer 3
Answer
Grade
None
100%
90%
83.33333%
80%
75%
70%
66.66667%
60%
50%
40%
33.33333%
30%
25%
20%
16.66667%
14.28571%
12.5%
11.11111%
10%
5%
Feedback
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100%
50%
33.33333%
25%
20%
10%
0%
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Wednesday, 12 June 2013, 1:05 PM
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Wednesday, 12 June 2013, 1:05 PM
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