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<font size="3">Considereu la següent equació de segon grau: </font><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»#p«/mi»«mo»=«/mo»«mn»0«/mn»«/math»</span></span></span><br /><br /><font size="3">Calculeu les dues solucions d'aquesta equació. Expresseu-les utilitzant el nombre complex </font> <span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»i«/mi»«mo»=«/mo»«msqrt»«mrow»«mo»-«/mo»«mn»1«/mn»«/mrow»«/msqrt»«/math»</span></span></span>,<font size="3"> en el cas de que us apareguin arrels de nombres negatius.<br /><br />Nota:<br />Introduiu les dues solucions entre claus i separades per una coma. Per exemple si les dues solucions són 3 i -3, heu d'introduir el següent: {3,-3}</font><br /><br /><br />
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<font size="3">Recordeu que existeix una fórmula per calcular les solucions d'una equació de segon grau:</font><br /> <div style="text-align: center"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mo»-«/mo»«mi»b«/mi»«mo»±«/mo»«msqrt»«mrow»«msup»«mi»b«/mi»«mn»2«/mn»«/msup»«mo»-«/mo»«mn»4«/mn»«mi»ac«/mi»«/mrow»«/msqrt»«/mrow»«mrow»«mn»2«/mn»«mi»a«/mi»«/mrow»«/mfrac»«/math»</span></span></span>.<br /></div><font size="3">Recordeu també que pot haver-hi solucions complexes, de manera que un discrimintant de la forma <span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msqrt»«mrow»«mo»-«/mo»«mn»23«/mn»«/mrow»«/msqrt»«/math»</span></span></span>cal simplificar-lo correctament, tot tenint en compte la definició de i, <span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»i«/mi»«mo»=«/mo»«msqrt»«mrow»«mo»-«/mo»«mn»1«/mn»«/mrow»«/msqrt»«/math»</span></span></span>: <span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msqrt»«mrow»«mo»-«/mo»«mn»23«/mn»«/mrow»«/msqrt»«mo»=«/mo»«mi»i«/mi»«msqrt»«mn»23«/mn»«/msqrt»«/math»</span></span></span>.</font>
No, case is unimportant
Yes, case must match
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Answer 1
Answer
Grade
None
100%
90%
83.33333%
80%
75%
70%
66.66667%
60%
50%
40%
33.33333%
30%
25%
20%
16.66667%
14.28571%
12.5%
11.11111%
10%
5%
Feedback
<font size="3">Recordeu que existeix una fórmula per calcular les solucions d'una equació de segon grau:</font><br /> <div style="text-align: center"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mo»-«/mo»«mi»b«/mi»«mo»±«/mo»«msqrt»«mrow»«msup»«mi»b«/mi»«mn»2«/mn»«/msup»«mo»-«/mo»«mn»4«/mn»«mi»ac«/mi»«/mrow»«/msqrt»«/mrow»«mrow»«mn»2«/mn»«mi»a«/mi»«/mrow»«/mfrac»«/math»</span></span></span>.<br /></div><font size="3">Recordeu també que pot haver-hi solucions complexes, de manera que un discrimintant de la forma <span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msqrt»«mrow»«mo»-«/mo»«mn»23«/mn»«/mrow»«/msqrt»«/math»</span></span></span>cal simplificar-lo correctament, tot tenint en compte la definició de i, <span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»i«/mi»«mo»=«/mo»«msqrt»«mrow»«mo»-«/mo»«mn»1«/mn»«/mrow»«/msqrt»«/math»</span></span></span>: <span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msqrt»«mrow»«mo»-«/mo»«mn»23«/mn»«/mrow»«/msqrt»«mo»=«/mo»«mi»i«/mi»«msqrt»«mn»23«/mn»«/msqrt»«/math»</span></span></span>.</font>
Answer 2
Answer
Grade
None
100%
90%
83.33333%
80%
75%
70%
66.66667%
60%
50%
40%
33.33333%
30%
25%
20%
16.66667%
14.28571%
12.5%
11.11111%
10%
5%
Feedback
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Penalty for each incorrect try
100%
50%
33.33333%
25%
20%
10%
0%
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Thursday, 10 December 2015, 10:53 AM
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