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<p><em><span style="font-family: 'times new roman', times, serif; font-size: large;">Si <span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»f«/mi»«/math»</span></span></span> es una función cuyo gráfico de la derivada <span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mi»d«/mi»«mi»f«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»x«/mi»«/mrow»«/mfrac»«/math»</span></span></span> corresponde a: </span></em><br /><br />#grafd<br /><br /><br /><br /><em><span style="font-family: 'times new roman', times, serif; font-size: large;">Entonces, el gráfico de la función <span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»f«/mi»«/math»</span></span></span> es: </span></em></p>
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<p><span style="font-size: large;"><em><span style="font-family: 'times new roman', times, serif;">Solución:<br /><br />Recordemos que si la derivada de una función evaluada en un punto da como resultado <span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mn»0«/mn»«/math»</span></span></span>, significa que dicho punto es un posible máximo o mínimo. En este caso, nos dan el gráfico de la derivada de la función; en ella anotaremos donde se hace </span></em></span><span style="font-size: large;"><em><span style="font-family: 'times new roman', times, serif;"><span style="font-size: large;"><em><span style="font-family: 'times new roman', times, serif;"><span class="nolink"><span class="nolink"><span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mn»0«/mn»«/math»</span></span></span></span></em></span> , obteniendo el siguiente gráfico:<br /><br />#grafp<br /><br />Luego, en esos puntos observamos que se alcanza un máximo o un mínimo. <br /><br />Analizando las alternativas, encontramos que la función que tiene 3 puntos extremos es el gráfico: <br /><br />#grafm<br /></span></em></span></p> <p><span style="font-size: large;"><em><span style="font-family: 'times new roman', times, serif;">Recuerda que también puedes analizar el gráfico de <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mi»d«/mi»«mi»f«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»x«/mi»«/mrow»«/mfrac»«/math»</span>de la siguiente manera:</span></em></span></p> <p><span style="font-size: large;"><em><span style="font-family: 'times new roman', times, serif;">- En los intervalos donde <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mi»d«/mi»«mi»f«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»x«/mi»«/mrow»«/mfrac»«mo»§gt;«/mo»«mn»0«/mn»«/math»</span>, la función <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»f«/mi»«/math»</span> es creciente.</span></em></span></p> <p><span style="font-size: large;"><em><span style="font-family: 'times new roman', times, serif;">- En los intervalos donde <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mi»d«/mi»«mi»f«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»x«/mi»«/mrow»«/mfrac»«mo»§lt;«/mo»«mn»0«/mn»«/math»</span>, la función <span class="nolink">«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»f«/mi»«/math»</span> es decreciente.<br /></span></em></span></p>
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Algorithm
Choice 1
Answer
#graf
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<i><font size="4" face="times new roman,times,serif">¡Excelente!</font></i>
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Choice 2
Answer
#grafr1
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<i><font size="4" face="times new roman,times,serif">Revisa el desarrollo para identificar tus errores. ¡Tú puedes!</font></i>
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Choice 3
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#grafr2
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<i><font size="4" face="times new roman,times,serif">Revisa el desarrollo para identificar tus errores. ¡Tú puedes!</font></i>
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Choice 4
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#grafr3
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<i><font size="4" face="times new roman,times,serif">Revisa el desarrollo para identificar tus errores. ¡Tú puedes!</font></i>
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Choice 5
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Choice 6
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For any partially correct response
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Options
Show the number of correct responses once the question has finished
For any incorrect response
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Settings for multiple tries
Penalty for each incorrect try
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Hint 2
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Clear incorrect responses
Show the number of correct responses
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Friday, 6 February 2015, 4:35 PM
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Friday, 6 February 2015, 4:35 PM
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