Behaviour being used: Adaptive mode
Minimum fraction: 0
Question summary: Calculeu la solució de l'equació [cos open parentheses 2 x close parentheses equals 1 plus 4 sin open parentheses x close parentheses]: x = π · k on k ∈ Z; x = ( ( π ) / ( 2 ) ) + π · k on k ∈ Z; x = - π + 2π · k on k ∈ Z; x = 2π · k on k ∈ Z
Right answer summary: x = π · k on k ∈ Z
Question state: todo