Technical information
Behaviour being used: Adaptive mode
Minimum fraction: 0
Question summary: Calculeu la solució de l'equació [tan open parentheses 2 x close parentheses equals negative tan open parentheses x close parentheses]: ( ( π ) / ( 3 ) ) + ( ( π ) / ( 2 ) ) k on k ∈ Z; ( ( π ) / ( 3 ) ) + 2πk on k ∈ Z; ( ( π ) / ( 3 ) ) k on k ∈ Z; ( ( π ) / ( 3 ) ) + πk on k ∈ Z
Right answer summary: ( ( π ) / ( 3 ) ) k on k ∈ Z
Question state: todo