Behaviour being used: Adaptive mode
Minimum fraction: 0
Question summary: Sabent que [a equals fraction numerator square root of 3 over denominator 2 end fraction], [b equals 0], [c equals negative fraction numerator square root of 2 over denominator 2 end fraction] i [d equals 1]. Emparelleu cada pregunta amb la seua resposta: {cos ( ( ( ( 5 ) · ( π ) ) / ( 4 ) ) ) =; sec ( 0 ); tan ( - ( ( ( π ) / ( 4 ) ) ) ) =; tan ( - ( π ) ) =; cos ( ( ( ( 7 ) · ( π ) ) / ( 6 ) ) ) =; sin ( ( ( π ) / ( 3 ) ) ) =} -> {d; -2c; -d; -a; c; a-d; b; a}
Right answer summary: cos ( ( ( ( 5 ) · ( π ) ) / ( 4 ) ) ) = -> c; sec ( 0 ) -> d; tan ( - ( ( ( π ) / ( 4 ) ) ) ) = -> -d; tan ( - ( π ) ) = -> b; cos ( ( ( ( 7 ) · ( π ) ) / ( 6 ) ) ) = -> -a; sin ( ( ( π ) / ( 3 ) ) ) = -> a
Question state: todo