Technical information
Behaviour being used: Adaptive mode
Minimum fraction: 0
Question summary: Calculeu: [limit as n rightwards arrow plus infinity of open parentheses fraction numerator 3 n squared minus 4 over denominator 2 n squared plus n minus 1 end fraction close parentheses to the power of 4 n end exponent equals]{+infinit; -infinit; 0}
Right answer summary: part 1: +infinit
Question state: todo