Behaviour being used: Adaptive mode
Minimum fraction: 0
Question summary: Calculeu: [limit as n rightwards arrow plus infinity of open parentheses fraction numerator negative 4 n squared minus 3 n plus 5 over denominator negative n squared plus 6 n minus 7 end fraction close parentheses to the power of fraction numerator n plus 3 over denominator 2 n minus 1 end fraction end exponent equals]_____
Right answer summary: part 1: 2
Question state: todo