Behaviour being used: Adaptive mode
Minimum fraction: 0
Question summary: Calculeu els següents límits: [limit as n rightwards arrow plus infinity of open parentheses fraction numerator negative 4 n squared minus 3 n plus 5 over denominator negative n squared plus 6 n minus 7 end fraction close parentheses to the power of fraction numerator n plus 3 over denominator 2 n minus 1 end fraction end exponent equals]_____ [limit as n rightwards arrow plus infinity of open parentheses fraction numerator negative n plus 9 over denominator 2 n minus 7 end fraction close parentheses to the power of n equals]_____ [limit as n rightwards arrow plus infinity of open parentheses fraction numerator 4 n minus 2 over denominator 4 n minus 3 end fraction close parentheses to the power of 4 n plus 3 end exponent equals]_____ [limit as n rightwards arrow plus infinity of open parentheses fraction numerator 3 n squared minus 4 over denominator 2 n squared plus n minus 1 end fraction close parentheses to the power of 4 n end exponent equals]{+infinit; 0; -infinit} [limit as n rightwards arrow plus infinity of open parentheses fraction numerator 3 n minus 4 over denominator n minus 1 end fraction close parentheses to the power of negative n end exponent equals]_____ [limit as n rightwards arrow plus infinity of open parentheses 1 minus fraction numerator 1 over denominator square root of n end fraction close parentheses to the power of n plus 2 end exponent equals]_____
Right answer summary: part 1: 2; part 2: 0; part 3: e; part 4: +infinit; part 5: 0; part 6: 0
Question state: todo