Preview question: T3. Solució del sistema

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Question summary: Tria la solució de cada sistema {[[x-y+z],[2·x-y+3·z],[-x+2·y-z]]=[[2],[8],[0]]; [[2·x+y+3·z],[-x+3·y+z],[-2·x+y+2·z]]=[[5],[6],[7]]; [[x+y-z],[2·x-y+z],[-x+y+3·z]]=[[2],[4],[2]]} -> {x=2, y=2, z=2; x=-1, y=1, z=2; x=2, y=1, z=1}

Right answer summary: [[x-y+z],[2·x-y+3·z],[-x+2·y-z]]=[[2],[8],[0]] -> x=2, y=2, z=2; [[2·x+y+3·z],[-x+3·y+z],[-2·x+y+2·z]]=[[5],[6],[7]] -> x=-1, y=1, z=2; [[x+y-z],[2·x-y+z],[-x+y+3·z]]=[[2],[4],[2]] -> x=2, y=1, z=1

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$open parentheses table row cell x minus y plus z end cell row cell 2 times x minus y plus 3 times z end cell row cell negative x plus 2 times y minus z end cell end table close parentheses equals open parentheses table row 2 row 8 row 0 end table close parentheses$	Answer 1
$open parentheses table row cell 2 times x plus y plus 3 times z end cell row cell negative x plus 3 times y plus z end cell row cell negative 2 times x plus y plus 2 times z end cell end table close parentheses equals open parentheses table row 5 row 6 row 7 end table close parentheses$	Answer 2
$open parentheses table row cell x plus y minus z end cell row cell 2 times x minus y plus z end cell row cell negative x plus y plus 3 times z end cell end table close parentheses equals open parentheses table row 2 row 4 row 2 end table close parentheses$	Answer 3

Preview question: T3. Solució del sistema

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