Behaviour being used: Adaptive mode
Minimum fraction: 0
Question summary: Donada la funció del gràfic #Dibuix, estudiem el límit en el punt: x=2 Si x= 2 [limit as x rightwards arrow # x _ 1 to the power of minus of f left parenthesis x right parenthesis space equals limit as x rightwards arrow # x _ 1 to the power of minus of open parentheses # f p close parentheses equals] {No existeix; -3; -5; 3} [limit as x rightwards arrow # x _ 1 to the power of plus of f left parenthesis x right parenthesis space equals limit as x rightwards arrow # x _ 1 to the power of plus of open parentheses # f s close parentheses equals] {3; No existeix; -3; -5} I, per tant, [limit as x rightwards arrow # x _ 1 of f left parenthesis x right parenthesis space equals]{-3; -5; No existeix; 3}
Right answer summary: part 1: -3; part 2: -5; part 3: No existeix
Question state: todo