Behaviour being used: Adaptive mode
Minimum fraction: 0
Question summary: Welche Äquivalenzumformungen sind richtig: {[fraction numerator x minus 1 over denominator 4 end fraction equals fraction numerator x plus 1 over denominator negative 3 end fraction left right double arrow fraction numerator 3 left parenthesis x minus 1 right parenthesis over denominator 12 end fraction equals fraction numerator negative 4 left parenthesis x plus 1 right parenthesis over denominator 12 end fraction]; [fraction numerator x minus 1 over denominator 4 end fraction equals fraction numerator x plus 1 over denominator negative 3 end fraction left right double arrow fraction numerator 3 left parenthesis x minus 1 right parenthesis over denominator 12 end fraction equals fraction numerator 4 left parenthesis x plus 1 right parenthesis over denominator 12 end fraction]; [fraction numerator x minus 1 over denominator 4 end fraction equals fraction numerator x plus 1 over denominator negative 3 end fraction left right double arrow fraction numerator 4 left parenthesis x minus 1 right parenthesis over denominator 12 end fraction equals fraction numerator negative 3 left parenthesis x plus 1 right parenthesis over denominator 12 end fraction]} -> {richtig; falsch}
Right answer summary: [fraction numerator x minus 1 over denominator 4 end fraction equals fraction numerator x plus 1 over denominator negative 3 end fraction left right double arrow fraction numerator 3 left parenthesis x minus 1 right parenthesis over denominator 12 end fraction equals fraction numerator negative 4 left parenthesis x plus 1 right parenthesis over denominator 12 end fraction] -> richtig; [fraction numerator x minus 1 over denominator 4 end fraction equals fraction numerator x plus 1 over denominator negative 3 end fraction left right double arrow fraction numerator 3 left parenthesis x minus 1 right parenthesis over denominator 12 end fraction equals fraction numerator 4 left parenthesis x plus 1 right parenthesis over denominator 12 end fraction] -> falsch; [fraction numerator x minus 1 over denominator 4 end fraction equals fraction numerator x plus 1 over denominator negative 3 end fraction left right double arrow fraction numerator 4 left parenthesis x minus 1 right parenthesis over denominator 12 end fraction equals fraction numerator negative 3 left parenthesis x plus 1 right parenthesis over denominator 12 end fraction] -> falsch
Question state: todo