Question 1

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Welche Äquivalenzumformungen sind richtig:

x over 3 minus fraction numerator x minus 1 over denominator 6 end fraction equals 12
left right double arrow fraction numerator 2 x minus left parenthesis x minus 1 right parenthesis over denominator 6 end fraction equals 12
x over 3 minus fraction numerator x minus 1 over denominator 6 end fraction equals 12
left right double arrow fraction numerator 2 x minus x minus 1 over denominator 6 end fraction equals 12
x over 3 minus fraction numerator x minus 1 over denominator 6 end fraction equals 12
left right double arrow fraction numerator x minus x plus 1 over denominator 6 end fraction equals 12
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