Behaviour being used: Adaptive mode
Minimum fraction: 0
Question summary: Nachfolgend sind vier Funktionen gegeben. [f left parenthesis x right parenthesis equals x to the power of n g left parenthesis x right parenthesis equals x to the power of n plus 1 end exponent h left parenthesis x right parenthesis equals x to the power of n minus 1 end exponent k left parenthesis x right parenthesis equals 1 over n x to the power of n] Ordnen Sie die Ableitungen richtig zu! {[n x to the power of n minus 1 end exponent]; [open parentheses n plus 1 close parentheses x to the power of n ]; [open parentheses n minus 1 close parentheses x to the power of n minus 2 end exponent ]; [x to the power of n minus 1 end exponent]} -> {k'(x); h'(x); g'(x); f'(x)}
Right answer summary: [n x to the power of n minus 1 end exponent] -> f'(x); [open parentheses n plus 1 close parentheses x to the power of n ] -> g'(x); [open parentheses n minus 1 close parentheses x to the power of n minus 2 end exponent ] -> h'(x); [x to the power of n minus 1 end exponent] -> k'(x)
Question state: todo