Question 1

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Question text

4 less or equal than fraction numerator 2 space x plus 6 over denominator 5 end fraction less than 9

The first step to solve this inequality would be to {:MCS:=multiply by~divide by~add~subtract}    .

The second step would be to {:MCS:=subtract~multiply by~divide by~add}    .

The third step would be to {:MCS:=divide by~add~subtract~multiply by}    .

The solution, in interval notation, is  

{:MCS:=[~]~(~)}   {:MCS:=)~[~]~(}

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