Behaviour being used: Adaptive mode
Minimum fraction: 0
Question summary: [# a less or equal than fraction numerator # b space x plus # c over denominator # d end fraction less than # e] The first step to solve this inequality would be to {:MCS:=multiply by~divide by~add~subtract} _____. The second step would be to {:MCS:=subtract~multiply by~divide by~add} _____. The third step would be to {:MCS:=divide by~add~subtract~multiply by} _____. The solution, in interval notation, is {:MCS:=[~]~(~)} _____ , _____ {:MCS:=)~[~]~(}
Right answer summary: part 1: 5; part 2: 6; part 3: 2; part 4: 7; part 5: 39/2
Question state: todo