Technical information
Behaviour being used: Adaptive mode
Minimum fraction: 0
Question summary: Si [f open parentheses # X close parentheses equals fraction numerator ln open parentheses # X close parentheses over denominator # pol1 end fraction]. Entonces, [fraction numerator d f left parenthesis # X right parenthesis over denominator d # X end fraction equals]
Right answer summary: The content can not be displayed.
Question state: todo