Question 1

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Dada la función j left parenthesis m right parenthesis del gráfico, resuelve la inecuación j open parentheses m close parentheses greater than 2

Obs: Escribe tu respuesta según corresponda, por ejemplo, si a space element of space straight real numbers , b element of straight real numbers y a less than b las respuestas posibles pueden ser:

left square bracket a comma b right parenthesis space semicolon space left parenthesis a comma b right square bracket space semicolon space left parenthesis a comma b right parenthesis space semicolon space left square bracket a comma b right square bracket space semicolon space left square bracket a comma plus infinity right parenthesis space semicolon space left parenthesis a comma plus infinity right parenthesis space space semicolon space left parenthesis negative infinity comma b right parenthesis space semicolon space left parenthesis negative infinity comma b right square bracket space semicolon
left parenthesis negative infinity comma a right parenthesis union left parenthesis b comma plus infinity right parenthesis space semicolon space left parenthesis negative infinity comma a right square bracket union left parenthesis b comma plus infinity right parenthesis space semicolon space left parenthesis negative infinity comma a right parenthesis union left square bracket b comma plus infinity right parenthesis space semicolon space left parenthesis negative infinity comma a right square bracket union left square bracket b comma plus infinity right parenthesis space

 

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