Preview question: 29. Probabilidad discreta

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Question summary: Sea [X] una variable aleatoria discreta con distribución dada por la tabla siguiente: {4.61,3.32,7.29,5.94,5.81,4.78,1.57} {0.142,0.166,0.141,0.146,0.136,0.0549,0.215} (la probabilidad de que [X] sea igual a un número que no esté en la tabla es cero) Calcule: * [E open parentheses X close parentheses] * [V a r open parentheses X close parentheses] * [P open parentheses X less than 4 close parentheses]

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$4.61$	$0.142$
$3.32$	$0.166$
$7.29$	$0.141$
$5.94$	$0.146$
$5.81$	$0.136$
$4.78$	$0.0549$
$1.57$	$0.215$

Preview question: 29. Probabilidad discreta

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