Preview question: 29. Discrete probability

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Question summary: Let [X] be a discrete random variable whose distribution is given by the table below. {0.111,7.02,4.55,3.32,7.26,5.86,9.32} {0.00712,0.0926,0.0142,0.0879,0.0865,0.159,0.553} (the probability that [X] equals a number outside of the left column is zero) Calculate: * [E open parentheses X close parentheses] * [V a r open parentheses X close parentheses] * [P open parentheses X less than 4 close parentheses]

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$0.111$	$0.00712$
$7.02$	$0.0926$
$4.55$	$0.0142$
$3.32$	$0.0879$
$7.26$	$0.0865$
$5.86$	$0.159$
$9.32$	$0.553$

Preview question: 29. Discrete probability

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