Behaviour being used: Adaptive mode
Minimum fraction: 0
Question summary: Ebatzi ondorengo ekuazio linealak. Resuelve las siguientes ecuaciones lineales. a. [begin mathsize 12px style fraction numerator 3 x minus 2 over denominator 4 end fraction minus fraction numerator 5 x minus 2 over denominator 8 end fraction plus 3 open parentheses x minus fraction numerator 4 x minus 1 over denominator 2 end fraction close parentheses equals 3 x end style] b. [begin mathsize 12px style open parentheses square root of 3 plus x close parentheses open parentheses square root of 3 minus x close parentheses equals negative x squared plus x plus 1 end style] c. [begin mathsize 12px style 3 over 4 open parentheses x minus 5 over 2 close parentheses minus 1 third open parentheses x over 12 minus 1 over 6 close parentheses equals fraction numerator 1 plus x over denominator 3 end fraction end style] d. [begin mathsize 12px style 3 over 4 open parentheses 2 x minus open parentheses 1 minus fraction numerator x plus 2 over denominator 3 end fraction close parentheses close parentheses equals fraction numerator 2 minus x over denominator 5 end fraction end style] Emaitza bakarrik adierazi, ez ipini aldagaia
Right answer summary: The content can not be displayed.
Question state: todo