Question 1

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Evaluate space the space polynomial space using space synthetic space substitution.

g left parenthesis 4 right parenthesis equals negative 1 text x end text cubed plus 3 text x end text squared minus 4 text x end text minus 23

In space the space first space blank comma space please space write space the space numbers comma space separated space by space colons comma space
that space appear space in space the space bottom space row.

In space the space second space blank space please space write space the space answer space left parenthesis the space value space of space the space polynomial
for space the space given space straight x minus value right parenthesis.

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