Behaviour being used: Adaptive mode
Minimum fraction: 0
Question summary: Suport teoretic: [O space s u b s tan t a space d i z o l v a t a space i n space a p a space d a space n a s t e r e space l a space o space s o l u t i e. C o n c e n t r a t i a space space u n e i space s o l u t i i space left parenthesis space c space right parenthesis space s e space d e d u c e space d i n space u r m a t o a r e a space p r o p o r t i e colon fraction numerator m a s a space s u b s tan t a space d i z o l v a t a space over denominator m a s a space s o l u t i e end fraction space equals space c over 100 space space left parenthesis equals c percent sign space right parenthesis. A l t f e l space s p u s comma space c o n c e n t r a t i a space left parenthesis space p r o c e n t u a l a space right parenthesis space n e space a r a t a space c a t e space g space d e space s u b s tan t a space d i z o l v a t a space s e space g a s e s c space i n space 100 g space space d e space s o l u t i e.] Problema: _SE DIZOLVA #A GRAME DE SARE IN #B ML APA._ _CONCENTRATIA SOLUTIEI OBTINUTE ESTE DE ... % _. ( 1 L de apa are masa de 1 Kg )
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Question state: todo