Question 1

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Fie matricele A=open parentheses table row 5 3 1 row cell negative 1 end cell cell negative 3 end cell cell negative 5 end cell row cell negative 4 end cell cell negative 4 end cell cell negative 1 end cell end table close parentheses şi B=open parentheses table row cell negative 5 end cell cell negative 5 end cell cell negative 3 end cell row 2 2 cell negative 1 end cell row cell negative 4 end cell 1 cell negative 3 end cell end table close parentheses.

a. Matricea A·B este 

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b. Matricea A- BT  este 

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c. Dacă X=open parentheses table row cell negative 2 times x end cell 0 1 row 0 cell 3 times x end cell 0 row 1 0 cell negative 1 end cell end table close parentheses şi C=A · X, atunci soluţiile din straight complex numbers ale ecuaţiei detopen parentheses table row cell negative 10 times x plus 1 end cell cell 9 times x end cell 4 row cell 2 times x minus 5 end cell cell negative 9 times x end cell 4 row cell 8 times x minus 1 end cell cell negative 12 times x end cell cell negative 3 end cell end table close parentheses=6 sunt

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