Preview question: Recapitulare transpusa

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Fie matricele A= $open parentheses table row cell negative 2 end cell cell negative 1 end cell 3 row 1 cell negative 1 end cell cell negative 3 end cell row 3 3 1 end table close parentheses$ , B= $open parentheses table row cell negative 3 end cell cell negative 2 end cell cell negative 2 end cell row cell negative 4 end cell 1 cell negative 4 end cell row cell negative 2 end cell 2 1 end table close parentheses$ şi C= $open parentheses table row 2 cell negative 4 end cell 2 row cell negative 4 end cell 3 cell negative 4 end cell row cell negative 4 end cell cell negative 3 end cell cell negative 2 end cell end table close parentheses$ . Pentru operaţiile de mai jos alegeţi matricea răpsuns corespunzătoare.

(A^T)^T+ B + C^T	Answer 1
(A+B)^T+ C^T	Answer 2
(A^T + B)^T + (C^T)^T	Answer 3
(A · B)^T + (C · A)^T	Answer 4

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Minimum fraction: 0

Question summary: Fie matricele A=[[-2,-1,3],[1,-1,-3],[3,3,1]], B=[[-3,-2,-2],[-4,1,-4],[-2,2,1]] şi C=[[2,-4,2],[-4,3,-4],[-4,-3,-2]]. Pentru operaţiile de mai jos alegeţi matricea răpsuns corespunzătoare. { (AT)T + B + CT; (A+B)T + CT; (AT + B)T + (CT)T; (A · B)T + (C · A)T} -> {[[-3,-7,-3],[-7,3,-10],[3,1,0]]; [[-3,-9,3],[-5,3,-5],[-3,-4,0]]; [[2,6,-24],[17,-20,0],[31,-26,-22]]; [[-3,-7,-3],[-7,3,2],[3,-11,0]]}

Right answer summary: (AT)T + B + CT -> [[-3,-7,-3],[-7,3,-10],[3,1,0]]; (A+B)T + CT -> [[-3,-7,-3],[-7,3,2],[3,-11,0]]; (AT + B)T + (CT)T -> [[-3,-9,3],[-5,3,-5],[-3,-4,0]]; (A · B)T + (C · A)T -> [[2,6,-24],[17,-20,0],[31,-26,-22]]

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