Technical information
Behaviour being used: Adaptive mode
Minimum fraction: 0
Question summary: [u with rightwards arrow on top space equals space left parenthesis # u1 space comma space # u2 space comma space m right parenthesis] eta [v with rightwards arrow on top space equals space left parenthesis m space comma space # v2 space comma space # v3 right parenthesis] bektoreak ortogonalak izateko m = _____ izan beharko da.
Right answer summary: part 1: 2
Question state: todo