Question 1

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Question text

Honako funtzioa kontuan hartuz:   f(x) = fraction numerator 3 times x squared plus 2 over denominator x minus 1 end fraction

Bere definizio eremua hau da: straight real numbers space minus space open curly brackets 1 close curly brackets

Asintota bertikaletako alboko limiteak kalkulatu:

stack L i m with x rightwards arrow 1 to the power of minus below space fraction numerator 3 times x squared plus 2 over denominator x minus 1 end fraction =

 stack L i m with x rightwards arrow 1 to the power of plus below space fraction numerator 3 times x squared plus 2 over denominator x minus 1 end fraction =

Eta asintota zehiarraren ekuazioa honakoa da:

y = ·x +  

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