Behaviour being used: Adaptive mode
Minimum fraction: 0
Question summary: Hallar la solución correcta: {[open parentheses x to the power of # a end exponent over x to the power of # b end exponent close parentheses squared]; [open parentheses x to the power of # a end exponent over x to the power of # b end exponent close parentheses squared times open parentheses x to the power of # a end exponent over x to the power of # b end exponent close parentheses to the power of negative 2 end exponent]; [open parentheses x to the power of # a end exponent over x to the power of # b end exponent close parentheses to the power of negative 2 end exponent]} -> {1/x^16; x^16; 1}
Right answer summary: [open parentheses x to the power of # a end exponent over x to the power of # b end exponent close parentheses squared] -> x^16; [open parentheses x to the power of # a end exponent over x to the power of # b end exponent close parentheses squared times open parentheses x to the power of # a end exponent over x to the power of # b end exponent close parentheses to the power of negative 2 end exponent] -> 1; [open parentheses x to the power of # a end exponent over x to the power of # b end exponent close parentheses to the power of negative 2 end exponent] -> 1/x^16
Question state: todo