Pre-Calc/Trig Unit 3: Analytic Trig and Applications/5.5 Double Angle Identities
Solve the problem.Suppose that for an electrical appliance, voltage is given ...
Solve the problem.
Suppose that for an electrical appliance, voltage is given by 
and amperage by 
where t is time in seconds. The wattage is given by 
Find the maximum wattage used by the appliance.]]>
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0nmzPC1v9iR7qaRlZA3mIcFWOUTaSdW0/ah8E6pbam9hB4qlnsNLfWGhufBus2vmW6g4dDLaLu3EEKFyWwcA4NGnfCHxZdWfiy98R+NbDUPFmtaOuiW2q6Vob2NvYQKJDvWBrmVnkLzMxbzQPlQBVwd168+EeqD4g6vrOn+JY7bw7rGgQ6He6Jc2DTunk/aPJlt5/OXy8faW3KyPu2jBU81nNSVOVmnLW1tutr3+S9fLUmPLz36afpf9X5K3ob3wk+I9r8W/hzoPiy0sb3TI9UtIrg2l/aT27xMyBmUCaONnUE4WQLtcYZcgiisf4L+HPGvg7RYfD3ia+0jUNL0WxttNsLvT9MaxkuzGpDTGP7TMqJs8pAvB3pK2FVkUFb1OXnbht09P6/4JhT5uRc+/U9IooorM1CiiigAooooAKKKKACiiigAooooAKKKKAP/Z/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAMCAgMCAgMDAwMEAwMEBQgFBQQEBQoHBwYIDAoMDAsKCwsNDhIQDQ4RDgsLEBYQERMUFRUVDA8XGBYUGBIUFRT/2wBDAQMEBAUEBQkFBQkUDQsNFBQUFBQUFBQUFBQUFBQUFBQUFBQUFBQUFBQUFBQUFBQUFBQUFBQUFBQUFBQUFBQUFBT/wAARCAARAC4DASIAAhEBAxEB/8QAHwAAAQUBAQEBAQEAAAAAAAAAAAECAwQFBgcICQoL/8QAtRAAAgEDAwIEAwUFBAQAAAF9AQIDAAQRBRIhMUEGE1FhByJxFDKBkaEII0KxwRVS0fAkM2JyggkKFhcYGRolJicoKSo0NTY3ODk6Q0RFRkdISUpTVFVWV1hZWmNkZWZnaGlqc3R1dnd4eXqDhIWGh4iJipKTlJWWl5iZmqKjpKWmp6ipqrKztLW2t7i5usLDxMXGx8jJytLT1NXW19jZ2uHi4+Tl5ufo6erx8vP09fb3+Pn6/8QAHwEAAwEBAQEBAQEBAQAAAAAAAAECAwQFBgcICQoL/8QAtREAAgECBAQDBAcFBAQAAQJ3AAECAxEEBSExBhJBUQdhcRMiMoEIFEKRobHBCSMzUvAVYnLRChYkNOEl8RcYGRomJygpKjU2Nzg5OkNERUZHSElKU1RVVldYWVpjZGVmZ2hpanN0dXZ3eHl6goOEhYaHiImKkpOUlZaXmJmaoqOkpaanqKmqsrO0tba3uLm6wsPExcbHyMnK0tPU1dbX2Nna4uPk5ebn6Onq8vP09fb3+Pn6/9oADAMBAAIRAxEAPwD6/i+OnxE0fwp8WkvLbQvE/jjwzq7aXouh6XplxYi6zbLdRu5kuJTJugcuQuzHlOBuyDXoHhL4jaz8QfG/hu60DUNIn8C3/huPW7mM2Er3avMcWwS5E4QK2JiVMJI8gjPz/Lp2fwgtbT416p8Qv7Qlc3um29mNL2kRRzxmRWuc7sMzROkeNvAQ8ndhU+Dnwftfg9p+t2VpqEuoW19qc93apLGEFjbO5aK0TBOUjLPtJ5w2OgABB2tzLZfkra97/F0tbe452e3f89fuXw99eqIf+GlPhENb/sb/AIWp4K/tj7R9k/s//hIrP7R5+7Z5Xl+Zu37vl24znjGazfjb458X+AvEfgG40m90Sx8I6nrEela3c6lpc11LbebkQOjpdRKgeUJDllcK0yscgFTpf8KB8MHW/wC1f7U8a/avtH2ry/8AhO9c+z7927HkfbPL2Z/5Z7dmOMY4roviX4Dsvif4B17wrqEslvbaraPb/aYDiW3cjKTRns8bhXU9mUGkm1yyerVm/Pute/np1BK8mtk/w8/l5Hkvj3xx8WbLxzcJ4c13wXD4V/t6w0ONdR8OXdxdI8yBpsyJfxo+zdHghFBLspwYzu+gK8g8R/BnxRceDvBWiaD41srS50LUY9Uv9R1vQzfSapcKxkZysVxbiLfI7u2M8kAYAOfTtMg1aK+1J9QvbK6s5Jg1jDbWbwyQRbACsrtK4lYtuIZVjABA2kjcRJq8Xrrp6Wj89776kO7kn0aX33l+lttPxNGiiimUFFFFABRRRQB//9k=
1.0000000
0.3333333
0
true
true
abc
189
Incorrect
404.46
Incorrect
101.115
Incorrect
202.23
Correct
Use an identity to write the expression as a single trigonometric function ...
Use an identity to write the expression as a single trigonometric function or as a single number.
2 cos2 22.5° - 1]]>
1.0000000
0.3333333
0
true
true
abc
]]>
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Incorrect. Think of "doubling" 22.5°.]]>
]]>
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Correct]]>
]]>
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Incorrect. Think of "doubling" 22.5°.]]>
]]>
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Incorrect. Think of "doubling" 22.5°.]]>
Use identities to find the indicated value for each angle measure.cos θ = , ...
Use identities to find the indicated value for each angle measure.
cos θ = 
, sin θ < 0
Find sin(2θ).]]>
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1.0000000
0.3333333
0
true
true
abc
]]>
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Incorrect. Did you use the identity: sin 2A=2 sin A cos A ?]]>
- 
]]>
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Correct]]>
]]>
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Incorrect. Did you use the identity: sin 2A=2 sin A cos A ?]]>
- 
]]>
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Incorrect. Did you use the identity: sin 2A=2 sin A cos A ?]]>
Write the product as a sum or difference of trigonometric functions.cos 44° ...
Write the product as a sum or difference of trigonometric functions.
cos 44° sin 15°]]>
1.0000000
0.3333333
0
true
true
abc
(cos 59° - cos 29°)]]>
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Incorrect
(sin 59° + sin 29°)]]>
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Incorrect
(cos 59° + cos 29°)]]>
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Incorrect
(sin 59° - sin 29°)]]>
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Correct