3º ESO/REACCIONES QUÍMICAS/REACTIVO LIMITANTE Combustión de metano Se desean quemar #vmet litros de gas metano, medidos en condiciones normales, utilizando #mox g de oxígeno, calcula

Gramos de dióxido de carbono que se obtendrían si el rendimiento fuera del 100 %.
El rendimiento de la reacción si se han obtenido #mag g de agua.

CH₄ + O₂ --> CO₂ + H₂O

]]> 1.0000000 0.3333333 0 0 Masa de CO2 =#gdirendimiento =#rend]]> <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>vmet</mi><mo>=</mo><mo> </mo><mi>aleatorio</mi><mo>(</mo><mn>20</mn><mo>,</mo><mn>60</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mox</mi><mo>=</mo><mo> </mo><mi>aleatorio</mi><mo>(</mo><mn>5</mn><mo>,</mo><mn>30</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>rend</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>70</mn><mo>,</mo><mn>98</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>gdi1</mi><mo>=</mo><mo>(</mo><mi>vmet</mi><mo>/</mo><mn>22</mn><mo>.</mo><mn>4</mn><mo>)</mo><mo>*</mo><mn>44</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>gdi2</mi><mo>=</mo><mo>(</mo><mi>mox</mi><mo>/</mo><mn>64</mn><mo>)</mo><mo>*</mo><mn>44</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><apply><csymbol definitionURL="http://www.wiris.com/XML/csymbol">if</csymbol><mrow><mi>gdi1</mi><mo>></mo><mi>gdi2</mi></mrow><mtable><mtr><mtd><mi>gdi</mi><mo>=</mo><mi>gdi2</mi><mo>*</mo><mn>1</mn><mo>.</mo><mn>0</mn></mtd></mtr><mtr><mtd><mi>mag</mi><mo>=</mo><mo>(</mo><mi>mox</mi><mo>/</mo><mn>64</mn><mo>)</mo><mo>*</mo><mn>36</mn><mo>*</mo><mi>rend</mi><mo>/</mo><mn>100</mn><mo>.</mo><mn>0</mn></mtd></mtr></mtable><mtable><mtr><mtd><mi>gdi</mi><mo>=</mo><mi>gdi1</mi><mo>*</mo><mn>1</mn><mo>.</mo><mn>0</mn></mtd></mtr><mtr><mtd><mi>mag</mi><mo>=</mo><mo>(</mo><mi>vmet</mi><mo>/</mo><mn>22</mn><mo>.</mo><mn>4</mn><mo>)</mo><mo>*</mo><mn>36</mn><mo>*</mo><mi>rend</mi><mo>/</mo><mn>100</mn><mo>.</mo><mn>0</mn></mtd></mtr></mtable></apply></math></input></command></group></library></session>]]></wirisCasSession><correctAnswers><correctAnswer type="mathml"><![CDATA[<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>M</mi><mi>a</mi><mi mathvariant="normal">s</mi><mi>a</mi><mo> </mo><mi>d</mi><mi mathvariant="normal">e</mi><mo> </mo><mi mathvariant="normal">C</mi><msub><mi>O</mi><mn>2</mn></msub><mo> </mo><mo>=</mo><mo>#</mo><mi mathvariant="normal">g</mi><mi>d</mi><mi mathvariant="normal">i</mi><mspace linebreak="newline"/><mi>r</mi><mi mathvariant="normal">e</mi><mi>n</mi><mi>d</mi><mi mathvariant="normal">i</mi><mi mathvariant="normal">m</mi><mi mathvariant="normal">i</mi><mi mathvariant="normal">e</mi><mi>n</mi><mi>t</mi><mi>o</mi><mo> </mo><mo>=</mo><mo>#</mo><mi>r</mi><mi mathvariant="normal">e</mi><mi>n</mi><mi>d</mi></math>]]></correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units">m, s, g, °, ', "</param><param name="decimalseparators">., \,</param><param name="unitprefixes">M, k, c, m</param><param name="groupoperators">(,[,{</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(--log(0.03))</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="inputField">textField</data><data name="inputCompound">true</data><data name="gradeCompound">distribute</data><data name="gradeCompoundDistribution"></data><data name="casSession"/></localData></question> Reactivo limitante Si hacemos reaccionar #mh g de sodio con #mn gramos de agua para formar hidrógeno e hidróxido de sodio.

Na + H₂O--> NaOH + H₂

Se forman {#1} litros de H₂ en condiciones normales y sobran {#2} gramos de {#3}

]]> 3.0000000 0.3333333 0 <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mh</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>10</mn><mo>,</mo><mn>30</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mn</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>10</mn><mo>,</mo><mn>20</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mah</mi><mo>=</mo><mi>mh</mi><mo>*</mo><mn>22</mn><mo>.</mo><mn>4</mn><mo>/</mo><mn>46</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>man</mi><mo>=</mo><mi>mn</mi><mo>*</mo><mn>22</mn><mo>.</mo><mn>4</mn><mo>/</mo><mn>36</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>p1</mi><mo>=</mo><mi>aleatorio</mi><mo>{</mo><mn>0</mn><mo>.</mo><mn>8</mn><mo>,</mo><mn>0</mn><mo>.</mo><mn>9</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>2</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>3</mn><mo>}</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>p2</mi><mo>=</mo><mi>aleatorio</mi><mo>{</mo><mn>0</mn><mo>.</mo><mn>7</mn><mo>,</mo><mn>0</mn><mo>.</mo><mn>85</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>1</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>5</mn><mo>}</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><apply><csymbol definitionURL="http://www.wiris.com/XML/csymbol">if</csymbol><mrow><mi>mah</mi><mo>></mo><mi>man</mi></mrow><mtable><mtr><mtd><mi>ga1</mi><mo>=</mo><mi>man</mi></mtd></mtr><mtr><mtd><mi>ga2</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>ga3</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>gh1</mi><mo>=</mo><mi>mh</mi><mo>-</mo><mo>(</mo><mi>mn</mi><mo>*</mo><mn>46</mn><mo>/</mo><mn>36</mn><mo>.</mo><mn>0</mn><mo>)</mo></mtd></mtr><mtr><mtd><mi>gh2</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>gh3</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>c2</mi><mo>=</mo><mo>"</mo><mi>Agua</mi><mo>"</mo></mtd></mtr><mtr><mtd><mi>c1</mi><mo>=</mo><mo>"</mo><mi>Sodio</mi><mo>"</mo></mtd></mtr></mtable><mtable><mtr><mtd><mi>ga1</mi><mo>=</mo><mi>mah</mi></mtd></mtr><mtr><mtd><mi>ga2</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>ga3</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>gh1</mi><mo>=</mo><mi>mn</mi><mo>-</mo><mo>(</mo><mi>mh</mi><mo>*</mo><mn>36</mn><mo>.</mo><mn>0</mn><mo>/</mo><mn>46</mn><mo>)</mo></mtd></mtr><mtr><mtd><mi>gh2</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>gh3</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>c1</mi><mo>=</mo><mo>"</mo><mi>Agua</mi><mo>"</mo></mtd></mtr><mtr><mtd><mi>c2</mi><mo>=</mo><mo>"</mo><mi>Sodio</mi><mo>"</mo></mtd></mtr></mtable></apply></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></library><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></session>]]></wirisCasSession><assertions><assertion name="syntax_expression"/><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(-4)</option><option name="relative_tolerance">false</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="casSession"/><data name="inputField">textField</data></localData></question> Reactivo limitante Si hacemos reaccionar #mh g de H₂ con #mn gramos de N₂ para formar amoniaco.

N₂ + H₂ --> NH₃

Se forman {#1} gramos de NH₃ y sobran {#2} gramos de {#3}

]]> 3.0000000 0.3333333 0 <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mh</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>2</mn><mo>,</mo><mn>8</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mn</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>10</mn><mo>,</mo><mn>50</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mah</mi><mo>=</mo><mi>mh</mi><mo>*</mo><mn>34</mn><mo>.</mo><mn>0</mn><mo>/</mo><mn>6</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>man</mi><mo>=</mo><mi>mn</mi><mo>*</mo><mn>34</mn><mo>.</mo><mn>0</mn><mo>/</mo><mn>28</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>p1</mi><mo>=</mo><mi>aleatorio</mi><mo>{</mo><mn>0</mn><mo>.</mo><mn>8</mn><mo>,</mo><mn>0</mn><mo>.</mo><mn>9</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>2</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>3</mn><mo>}</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>p2</mi><mo>=</mo><mi>aleatorio</mi><mo>{</mo><mn>0</mn><mo>.</mo><mn>7</mn><mo>,</mo><mn>0</mn><mo>.</mo><mn>85</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>1</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>5</mn><mo>}</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><apply><csymbol definitionURL="http://www.wiris.com/XML/csymbol">if</csymbol><mrow><mi>mah</mi><mo>></mo><mi>man</mi></mrow><mtable><mtr><mtd><mi>ga1</mi><mo>=</mo><mi>man</mi></mtd></mtr><mtr><mtd><mi>ga2</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>ga3</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>gh1</mi><mo>=</mo><mi>mh</mi><mo>-</mo><mo>(</mo><mi>mn</mi><mo>*</mo><mn>6</mn><mo>.</mo><mn>0</mn><mo>/</mo><mn>28</mn><mo>)</mo></mtd></mtr><mtr><mtd><mi>gh2</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>gh3</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>c1</mi><mo>=</mo><mo>"</mo><mi>Hidrógeno</mi><mo>"</mo></mtd></mtr><mtr><mtd><mi>c2</mi><mo>=</mo><mo>"</mo><mi>Nitrógeno</mi><mo>"</mo></mtd></mtr></mtable><mtable><mtr><mtd><mi>ga1</mi><mo>=</mo><mi>mah</mi></mtd></mtr><mtr><mtd><mi>ga2</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>ga3</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>gh1</mi><mo>=</mo><mi>mn</mi><mo>-</mo><mo>(</mo><mi>mh</mi><mo>*</mo><mn>28</mn><mo>.</mo><mn>0</mn><mo>/</mo><mn>6</mn><mo>)</mo></mtd></mtr><mtr><mtd><mi>gh2</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>gh3</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>c2</mi><mo>=</mo><mo>"</mo><mi>Hidrógeno</mi><mo>"</mo></mtd></mtr><mtr><mtd><mi>c1</mi><mo>=</mo><mo>"</mo><mi>Nitrógeno</mi><mo>"</mo></mtd></mtr></mtable></apply></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></library><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></session>]]></wirisCasSession><assertions><assertion name="syntax_expression"/><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(-4)</option><option name="relative_tolerance">false</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="casSession"/><data name="inputField">textField</data></localData></question> Reactivo limitante Si hacemos reaccionar #mh g de FeS₂ con #mn gramos de O₂ para formar dióxido de azufre.

FeS₂ + O₂ --> SO₂ + Fe₂O₃

Se forman {#1} gramos de SO₂ y sobran {#2} gramos de {#3}

Masas atómicas: Fe = 55.8; O=16; S=32

]]> 3.0000000 0.3333333 0 <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mh</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>2</mn><mo>,</mo><mn>8</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mn</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>10</mn><mo>,</mo><mn>50</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mah</mi><mo>=</mo><mi>mh</mi><mo>*</mo><mn>8</mn><mo>*</mo><mn>64</mn><mo>.</mo><mn>0</mn><mo>/</mo><mo>(</mo><mn>4</mn><mo>*</mo><mn>119</mn><mo>.</mo><mn>8</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>man</mi><mo>=</mo><mi>mn</mi><mo>*</mo><mn>8</mn><mo>*</mo><mn>64</mn><mo>.</mo><mn>0</mn><mo>/</mo><mo>(</mo><mn>11</mn><mo>*</mo><mn>32</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>p1</mi><mo>=</mo><mi>aleatorio</mi><mo>{</mo><mn>0</mn><mo>.</mo><mn>8</mn><mo>,</mo><mn>0</mn><mo>.</mo><mn>9</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>2</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>3</mn><mo>}</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>p2</mi><mo>=</mo><mi>aleatorio</mi><mo>{</mo><mn>0</mn><mo>.</mo><mn>7</mn><mo>,</mo><mn>0</mn><mo>.</mo><mn>85</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>1</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>5</mn><mo>}</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><apply><csymbol definitionURL="http://www.wiris.com/XML/csymbol">if</csymbol><mrow><mi>mah</mi><mo>></mo><mi>man</mi></mrow><mtable><mtr><mtd><mi>ga1</mi><mo>=</mo><mi>man</mi></mtd></mtr><mtr><mtd><mi>ga2</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>ga3</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>gh1</mi><mo>=</mo><mi>mh</mi><mo>-</mo><mo>(</mo><mi>mn</mi><mo>*</mo><mn>119</mn><mo>.</mo><mn>8</mn><mo>/</mo><mn>88</mn><mo>)</mo></mtd></mtr><mtr><mtd><mi>gh2</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>gh3</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>c1</mi><mo>=</mo><mo>"</mo><mi>FeS2</mi><mo>"</mo></mtd></mtr><mtr><mtd><mi>c2</mi><mo>=</mo><mo>"</mo><mi>Oxígeno</mi><mo>"</mo></mtd></mtr></mtable><mtable><mtr><mtd><mi>ga1</mi><mo>=</mo><mi>mah</mi></mtd></mtr><mtr><mtd><mi>ga2</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>ga3</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>gh1</mi><mo>=</mo><mi>mn</mi><mo>-</mo><mo>(</mo><mi>mh</mi><mo>*</mo><mn>88</mn><mo>/</mo><mn>119</mn><mo>.</mo><mn>8</mn><mo>)</mo></mtd></mtr><mtr><mtd><mi>gh2</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>gh3</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>c2</mi><mo>=</mo><mo>"</mo><mi>FeS2</mi><mo>"</mo></mtd></mtr><mtr><mtd><mi>c1</mi><mo>=</mo><mo>"</mo><mi>Oxígeno</mi><mo>"</mo></mtd></mtr></mtable></apply></math></input></command></group></library><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></session>]]></wirisCasSession><assertions><assertion name="syntax_expression"/><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(-4)</option><option name="relative_tolerance">false</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="casSession"/><data name="inputField">textField</data></localData></question> Reactivo limitante En el proceso de formación del agua a partir de sus elementos, calcule: a) la masa de agua en gramos que se forma a partir de de #mh g de hidrógeno y #mo gramos de oxígeno. b) Indique la masa, en gramos, de reactivo que quedarán al finalizar la reacción (si de alguno no queda nada indique 0)

H₂ + O₂ -> H₂O

]]> 1.0000000 0.3333333 0 0 Agua =#maghidróg. =#mhidoxígeno =#mox]]> <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mh</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>2</mn><mo>,</mo><mn>7</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mo</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>10</mn><mo>,</mo><mn>60</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mag1</mi><mo>=</mo><mi>mh</mi><mo>*</mo><mn>36</mn><mo>/</mo><mn>4</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mag2</mi><mo>=</mo><mi>mo</mi><mo>*</mo><mn>36</mn><mo>/</mo><mn>32</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><apply><csymbol definitionURL="http://www.wiris.com/XML/csymbol">if</csymbol><mrow><mi>mag1</mi><mo>></mo><mi>mag2</mi></mrow><mtable><mtr><mtd><mi>mag</mi><mo>=</mo><mi>mag2</mi><mo>*</mo><mn>1</mn><mo>.</mo><mn>0</mn></mtd></mtr><mtr><mtd><mi>mox</mi><mo>=</mo><mn>0</mn></mtd></mtr><mtr><mtd><mi>mhid</mi><mo>=</mo><mo>(</mo><mi>mh</mi><mo>-</mo><mo>(</mo><mi>mo</mi><mo>*</mo><mn>4</mn><mo>/</mo><mn>32</mn><mo>)</mo><mo>)</mo><mo>*</mo><mn>1</mn><mo>.</mo><mn>0</mn></mtd></mtr></mtable><mtable><mtr><mtd><mi>mag</mi><mo>=</mo><mi>mag1</mi><mo>*</mo><mn>1</mn><mo>.</mo><mn>0</mn></mtd></mtr><mtr><mtd><mi>mhid</mi><mo>=</mo><mn>0</mn></mtd></mtr><mtr><mtd><mi>mox</mi><mo>=</mo><mo>(</mo><mi>mo</mi><mo>-</mo><mi>mh</mi><mo>*</mo><mn>32</mn><mo>/</mo><mn>4</mn><mo>)</mo><mo>*</mo><mn>1</mn><mo>.</mo><mn>0</mn></mtd></mtr></mtable></apply></math></input></command></group></library></session>]]></wirisCasSession><correctAnswers><correctAnswer type="mathml"><![CDATA[<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>A</mi><mi mathvariant="normal">g</mi><mi>u</mi><mi>a</mi><mo> </mo><mo>=</mo><mo>#</mo><mi mathvariant="normal">m</mi><mi>a</mi><mi mathvariant="normal">g</mi><mspace linebreak="newline"/><mi mathvariant="normal">h</mi><mi mathvariant="normal">i</mi><mi>d</mi><mi>r</mi><mi>ó</mi><mi mathvariant="normal">g</mi><mo>.</mo><mo> </mo><mo> </mo><mo> </mo><mo>=</mo><mo>#</mo><mi mathvariant="normal">m</mi><mi mathvariant="normal">h</mi><mi mathvariant="normal">i</mi><mi>d</mi><mspace linebreak="newline"/><mi>o</mi><mi>x</mi><mi>í</mi><mi mathvariant="normal">g</mi><mi mathvariant="normal">e</mi><mi>n</mi><mi>o</mi><mo> </mo><mo>=</mo><mo>#</mo><mi mathvariant="normal">m</mi><mi>o</mi><mi>x</mi></math>]]></correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units"><![CDATA[m, s, g, °, ', ", sr, E, K, mol, cd, rad, h, min, l, N, Pa, Hz, W, J, C, V, Ω, F, S, Wb, b, H, T, lx, lm, Gy, Bq, Sv, kat]]></param><param name="unitprefixes">M, k, c, m</param><param name="groupoperators">(,[,{</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="relative_tolerance">true</option><option name="tolerance">10^(--log(0.03))</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="inputField">textField</data><data name="inputCompound">true</data><data name="gradeCompound">distribute</data><data name="gradeCompoundDistribution"></data><data name="casSession"/></localData></question> Reactivo limitante (con ninguno) Si hacemos reaccionar #mh g de H₂ con #mn gramos de N₂ para formar amoniaco.

N₂ + H₂ --> NH₃

Se forman {#1} gramos de NH₃ y sobran {#2} gramos de {#3}

]]> 3.0000000 0.3333333 0 <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mh</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>2</mn><mo>,</mo><mn>8</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mn</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>10</mn><mo>,</mo><mn>50</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mah</mi><mo>=</mo><mi>mh</mi><mo>*</mo><mn>34</mn><mo>.</mo><mn>0</mn><mo>/</mo><mn>6</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>man</mi><mo>=</mo><mi>mn</mi><mo>*</mo><mn>34</mn><mo>.</mo><mn>0</mn><mo>/</mo><mn>28</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>p1</mi><mo>=</mo><mi>aleatorio</mi><mo>{</mo><mn>0</mn><mo>.</mo><mn>8</mn><mo>,</mo><mn>0</mn><mo>.</mo><mn>9</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>2</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>3</mn><mo>}</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>p2</mi><mo>=</mo><mi>aleatorio</mi><mo>{</mo><mn>0</mn><mo>.</mo><mn>7</mn><mo>,</mo><mn>0</mn><mo>.</mo><mn>85</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>1</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>5</mn><mo>}</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><apply><csymbol definitionURL="http://www.wiris.com/XML/csymbol">if</csymbol><mrow><mi>mah</mi><mo>></mo><mi>man</mi></mrow><mtable><mtr><mtd><mi>ga1</mi><mo>=</mo><mi>man</mi><mo>*</mo><mo>(</mo><mi>p1</mi><mo>+</mo><mi>p2</mi><mo>)</mo></mtd></mtr><mtr><mtd><mi>ga2</mi><mo>=</mo><mi>man</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>ga3</mi><mo>=</mo><mi>man</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>ga4</mi><mo>=</mo><mi>man</mi></mtd></mtr><mtr><mtd><mi>gh1</mi><mo>=</mo><mi>mh</mi><mo>-</mo><mo>(</mo><mi>mn</mi><mo>*</mo><mn>6</mn><mo>/</mo><mn>28</mn><mo>.</mo><mn>0</mn><mo>)</mo></mtd></mtr><mtr><mtd><mi>gh2</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>gh3</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>c1</mi><mo>=</mo><mo>"</mo><mi>Hidrógeno</mi><mo>"</mo></mtd></mtr><mtr><mtd><mi>c2</mi><mo>=</mo><mo>"</mo><mi>Nitrógeno</mi><mo>"</mo></mtd></mtr></mtable><mtable><mtr><mtd><mi>ga1</mi><mo>=</mo><mi>mah</mi><mo>*</mo><mo>(</mo><mi>p1</mi><mo>+</mo><mi>p2</mi><mo>)</mo></mtd></mtr><mtr><mtd><mi>ga2</mi><mo>=</mo><mi>mah</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>ga3</mi><mo>=</mo><mi>mah</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>ga4</mi><mo>=</mo><mi>mah</mi></mtd></mtr><mtr><mtd><mi>gh1</mi><mo>=</mo><mi>mn</mi><mo>-</mo><mo>(</mo><mi>mh</mi><mo>*</mo><mn>28</mn><mo>.</mo><mn>0</mn><mo>/</mo><mn>6</mn><mo>)</mo></mtd></mtr><mtr><mtd><mi>gh2</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>gh3</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>c2</mi><mo>=</mo><mo>"</mo><mi>Hidrógeno</mi><mo>"</mo></mtd></mtr><mtr><mtd><mi>c1</mi><mo>=</mo><mo>"</mo><mi>Nitrógeno</mi><mo>"</mo></mtd></mtr></mtable></apply></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></library><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></session>]]></wirisCasSession><assertions><assertion name="syntax_expression"/><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(-4)</option><option name="relative_tolerance">false</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="casSession"/></localData></question> Reactivo limitante dióxido de azufre Si hacemos reaccionar #mdo g de SO₂ con #mo gramos de O₂ para formar trióxido de azufre.

SO₂ + O₂ --> SO₃

Se forman {#1} gramos de SO₃ y sobran {#2} gramos de {#3}

Masas atómicas = O = 16; S=32

]]> 3.0000000 0.3333333 0 <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mdo</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>20</mn><mo>,</mo><mn>80</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mo</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>10</mn><mo>,</mo><mn>50</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mtd</mi><mo>=</mo><mi>mdo</mi><mo>*</mo><mn>80</mn><mo>.</mo><mn>0</mn><mo>/</mo><mn>64</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mto</mi><mo>=</mo><mi>mo</mi><mo>*</mo><mn>160</mn><mo>.</mo><mn>0</mn><mo>/</mo><mn>32</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>p1</mi><mo>=</mo><mi>aleatorio</mi><mo>{</mo><mn>0</mn><mo>.</mo><mn>8</mn><mo>,</mo><mn>0</mn><mo>.</mo><mn>9</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>2</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>3</mn><mo>}</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>p2</mi><mo>=</mo><mi>aleatorio</mi><mo>{</mo><mn>0</mn><mo>.</mo><mn>7</mn><mo>,</mo><mn>0</mn><mo>.</mo><mn>85</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>1</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>5</mn><mo>}</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><apply><csymbol definitionURL="http://www.wiris.com/XML/csymbol">if</csymbol><mrow><mi>mtd</mi><mo>></mo><mi>mto</mi></mrow><mtable><mtr><mtd><mi>ga1</mi><mo>=</mo><mi>mto</mi></mtd></mtr><mtr><mtd><mi>ga2</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>ga3</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>gh1</mi><mo>=</mo><mi>mdo</mi><mo>-</mo><mo>(</mo><mi>mo</mi><mo>*</mo><mn>128</mn><mo>.</mo><mn>0</mn><mo>/</mo><mn>32</mn><mo>)</mo></mtd></mtr><mtr><mtd><mi>gh2</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>gh3</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>c1</mi><mo>=</mo><mo>"</mo><mi>Dióxido</mi><mo> </mo><mi>de</mi><mo> </mo><mi>azufre</mi><mo>"</mo></mtd></mtr><mtr><mtd><mi>c2</mi><mo>=</mo><mo>"</mo><mi>Oxígeno</mi><mo>"</mo></mtd></mtr></mtable><mtable><mtr><mtd><mi>ga1</mi><mo>=</mo><mi>mtd</mi></mtd></mtr><mtr><mtd><mi>ga2</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>ga3</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>gh1</mi><mo>=</mo><mi>mo</mi><mo>-</mo><mo>(</mo><mi>mdo</mi><mo>*</mo><mn>32</mn><mo>.</mo><mn>0</mn><mo>/</mo><mn>128</mn><mo>.</mo><mn>0</mn><mo>)</mo></mtd></mtr><mtr><mtd><mi>gh2</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>gh3</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>c2</mi><mo>=</mo><mo>"</mo><mi>Dióxido</mi><mo> </mo><mi>de</mi><mo> </mo><mi>azufre</mi><mo>"</mo></mtd></mtr><mtr><mtd><mi>c1</mi><mo>=</mo><mo>"</mo><mi>Oxígeno</mi><mo>"</mo></mtd></mtr></mtable></apply></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></library><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></session>]]></wirisCasSession><assertions><assertion name="syntax_expression"/><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(-4)</option><option name="relative_tolerance">false</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="casSession"/></localData></question> Reactivo limitante dióxido de azufre volúmenes Si hacemos reaccionar #ldo litros de SO₂ con #lo litros de O₂ para formar trióxido de azufre.

SO₂ + O₂ --> SO₃

Se forman {#1} litros de SO₃ y sobran {#2} litros de {#3}

Todos los gases están en condiciones normales. Masas atómicas = O = 16; S=32

]]> 3.0000000 0.3333333 0 <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>ldo</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>20</mn><mo>,</mo><mn>80</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>lo</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>10</mn><mo>,</mo><mn>50</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>ltd</mi><mo>=</mo><mi>ldo</mi></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>lto</mi><mo>=</mo><mn>2</mn><mo>.</mo><mn>0</mn><mo>*</mo><mi>lo</mi></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>p1</mi><mo>=</mo><mi>aleatorio</mi><mo>{</mo><mn>0</mn><mo>.</mo><mn>8</mn><mo>,</mo><mn>0</mn><mo>.</mo><mn>9</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>2</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>3</mn><mo>}</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>p2</mi><mo>=</mo><mi>aleatorio</mi><mo>{</mo><mn>0</mn><mo>.</mo><mn>7</mn><mo>,</mo><mn>0</mn><mo>.</mo><mn>85</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>1</mn><mo>,</mo><mn>1</mn><mo>.</mo><mn>5</mn><mo>}</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><apply><csymbol definitionURL="http://www.wiris.com/XML/csymbol">if</csymbol><mrow><mi>ltd</mi><mo>></mo><mi>lto</mi></mrow><mtable><mtr><mtd><mi>ga1</mi><mo>=</mo><mi>lto</mi></mtd></mtr><mtr><mtd><mi>ga2</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>ga3</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>gh1</mi><mo>=</mo><mi>ldo</mi><mo>-</mo><mo>(</mo><mi>lo</mi><mo>*</mo><mn>2</mn><mo>.</mo><mn>0</mn><mo>)</mo></mtd></mtr><mtr><mtd><mi>gh2</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>gh3</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>c1</mi><mo>=</mo><mo>"</mo><mi>Dióxido</mi><mo> </mo><mi>de</mi><mo> </mo><mi>azufre</mi><mo>"</mo></mtd></mtr><mtr><mtd><mi>c2</mi><mo>=</mo><mo>"</mo><mi>Oxígeno</mi><mo>"</mo></mtd></mtr></mtable><mtable><mtr><mtd><mi>ga1</mi><mo>=</mo><mi>ltd</mi></mtd></mtr><mtr><mtd><mi>ga2</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>ga3</mi><mo>=</mo><mi>ga1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>gh1</mi><mo>=</mo><mi>lo</mi><mo>-</mo><mo>(</mo><mi>ldo</mi><mo>/</mo><mn>2</mn><mo>.</mo><mn>0</mn><mo>)</mo></mtd></mtr><mtr><mtd><mi>gh2</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p1</mi></mtd></mtr><mtr><mtd><mi>gh3</mi><mo>=</mo><mi>gh1</mi><mo>*</mo><mi>p2</mi></mtd></mtr><mtr><mtd><mi>c2</mi><mo>=</mo><mo>"</mo><mi>Dióxido</mi><mo> </mo><mi>de</mi><mo> </mo><mi>azufre</mi><mo>"</mo></mtd></mtr><mtr><mtd><mi>c1</mi><mo>=</mo><mo>"</mo><mi>Oxígeno</mi><mo>"</mo></mtd></mtr></mtable></apply></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></library><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></session>]]></wirisCasSession><assertions><assertion name="syntax_expression"/><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(-4)</option><option name="relative_tolerance">false</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="casSession"/></localData></question> Reactivo limitante yodo e hidrógeno En un reactor se introducen #myod g de I₂ y #vhid L de H₂ en condiciones normales. Determina:

a) ¿Cuál es el reactivo limitante? (1: yodo; 2: hidrógeno)

b) ¿Cuántos gramos de HI se producen en la reacción?

H₂ + I₂ -> HI

Datos (A); H= 1; I= 126.9

]]> 1.0000000 0.3333333 0 0 Reactivo limitante =#rliMasa de HI =#mhi]]> <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>myod</mi><mo>=</mo><mo> </mo><mi>aleatorio</mi><mo>(</mo><mn>30</mn><mo>,</mo><mn>90</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>vhid</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>2</mn><mo>,</mo><mn>12</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mhi1</mi><mo>=</mo><mi>myod</mi><mo>*</mo><mn>2</mn><mo>*</mo><mn>127</mn><mo>.</mo><mn>9</mn><mo>/</mo><mn>253</mn><mo>.</mo><mn>8</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mhi2</mi><mo>=</mo><mi>vhid</mi><mo>*</mo><mn>2</mn><mo>*</mo><mn>127</mn><mo>.</mo><mn>9</mn><mo>/</mo><mn>22</mn><mo>.</mo><mn>4</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><apply><csymbol definitionURL="http://www.wiris.com/XML/csymbol">if</csymbol><mrow><mi>mhi1</mi><mo>></mo><mi>mhi2</mi></mrow><mtable><mtr><mtd><mi>mhi</mi><mo>=</mo><mi>mhi2</mi></mtd></mtr><mtr><mtd><mi>rli</mi><mo>=</mo><mn>2</mn></mtd></mtr></mtable><mtable><mtr><mtd><mi>mhi</mi><mo>=</mo><mi>mhi1</mi></mtd></mtr><mtr><mtd><mi>rli</mi><mo>=</mo><mn>1</mn></mtd></mtr></mtable></apply></math></input></command></group></library></session>]]></wirisCasSession><correctAnswers><correctAnswer type="mathml"><![CDATA[<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>R</mi><mi mathvariant="normal">e</mi><mi>a</mi><mi>c</mi><mi>t</mi><mi mathvariant="normal">i</mi><mi>v</mi><mi>o</mi><mo> </mo><mi mathvariant="normal">l</mi><mi mathvariant="normal">i</mi><mi mathvariant="normal">m</mi><mi mathvariant="normal">i</mi><mi>t</mi><mi>a</mi><mi>n</mi><mi>t</mi><mi mathvariant="normal">e</mi><mo> </mo><mo>=</mo><mo>#</mo><mi>r</mi><mi mathvariant="normal">l</mi><mi mathvariant="normal">i</mi><mspace linebreak="newline"/><mi>M</mi><mi>a</mi><mi mathvariant="normal">s</mi><mi>a</mi><mo> </mo><mi>d</mi><mi mathvariant="normal">e</mi><mo> </mo><mi mathvariant="normal">H</mi><mi>I</mi><mo> </mo><mo>=</mo><mo>#</mo><mi mathvariant="normal">m</mi><mi mathvariant="normal">h</mi><mi mathvariant="normal">i</mi></math>]]></correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units">m, s, g, °, ', "</param><param name="decimalseparators">., \,</param><param name="unitprefixes">M, k, c, m</param><param name="groupoperators">(,[,{</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(--log(0.03))</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="inputField">textField</data><data name="gradeCompound">distribute</data><data name="gradeCompoundDistribution"></data><data name="casSession"/><data name="inputCompound">true</data></localData></question>