3º ESO/DISOLUCIONES/DISOLUCIONES Y REACCIONES Carbonato de calcio y clorhidrico En vaso de precipitado ponemos #mca gramos de carbonato de calcio y #vola cm³ de ácido clorhídrico #mac M . Determina:

HCl + CaCO₃ --> CaCl₂ + CO₂ + H₂O

¿Cuál es el reactivo limitante (1= carbonato, 2= ácido)
La masa de cloruro de calcio que se forma.

Datos (A): Ca=40; Cl=35.5; H=1; O=16

]]> 1.0000000 0.3333333 0 0 Reactivo limitante = #rlMasa de cloruro = #mcl]]> <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mca</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>10</mn><mo>,</mo><mn>30</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>vola</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>100</mn><mo>,</mo><mn>200</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mac</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>5</mn><mo>,</mo><mn>20</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mac</mi><mo>=</mo><mi>mac</mi><mo>*</mo><mn>1</mn><mo>.</mo><mn>0</mn><mo>/</mo><mn>10</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mola</mi><mo>=</mo><mi>vola</mi><mo>*</mo><mi>mac</mi><mo>/</mo><mn>1000</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>molca</mi><mo>=</mo><mi>mca</mi><mo>/</mo><mn>100</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><apply><csymbol definitionURL="http://www.wiris.com/XML/csymbol">if</csymbol><mrow><mi>mola</mi><mo>></mo><mn>2</mn><mo>*</mo><mi>molca</mi></mrow><mtable><mtr><mtd><mi>mcl</mi><mo>=</mo><mn>111</mn><mo>*</mo><mi>molca</mi></mtd></mtr><mtr><mtd><mi>rl</mi><mo>=</mo><mn>1</mn></mtd></mtr></mtable><mtable><mtr><mtd><mi>mcl</mi><mo>=</mo><mn>111</mn><mo>*</mo><mi>mola</mi><mo>/</mo><mn>2</mn></mtd></mtr><mtr><mtd><mi>rl</mi><mo>=</mo><mn>2</mn></mtd></mtr></mtable></apply></math></input></command></group></library></session>]]></wirisCasSession><correctAnswers><correctAnswer type="mathml"><![CDATA[<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>R</mi><mi mathvariant="normal">e</mi><mi>a</mi><mi>c</mi><mi>t</mi><mi mathvariant="normal">i</mi><mi>v</mi><mi>o</mi><mo> </mo><mi mathvariant="normal">l</mi><mi mathvariant="normal">i</mi><mi mathvariant="normal">m</mi><mi mathvariant="normal">i</mi><mi>t</mi><mi>a</mi><mi>n</mi><mi>t</mi><mi mathvariant="normal">e</mi><mo> </mo><mo>=</mo><mo> </mo><mo>#</mo><mi>r</mi><mi mathvariant="normal">l</mi><mspace linebreak="newline"/><mi>M</mi><mi>a</mi><mi mathvariant="normal">s</mi><mi>a</mi><mo> </mo><mi>d</mi><mi mathvariant="normal">e</mi><mo> </mo><mi>cl</mi><mi>o</mi><mi>r</mi><mi>u</mi><mi>r</mi><mi>o</mi><mo> </mo><mo>=</mo><mo> </mo><mo>#</mo><mi mathvariant="normal">m</mi><mi>cl</mi></math>]]></correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units"><![CDATA[m, s, g, °, ', ", sr, E, K, mol, cd, rad, h, min, l, N, Pa, Hz, W, J, C, V, Ω, F, S, Wb, b, H, T, lx, lm, Gy, Bq, Sv, kat]]></param><param name="unitprefixes">M, k, c, m</param><param name="groupoperators">(,[,{</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(--log(0.03))</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="inputField">textField</data><data name="gradeCompound">distribute</data><data name="gradeCompoundDistribution"></data><data name="casSession"/><data name="inputCompound">true</data></localData></question> hidróxido de sodio y ácido sulfúrico En vaso de precipitado ponemos #mhi gramos de hidróxido de sodio y #vola cm³ de ácido sulfúrico #mac M . Determina:

NaOH + H₂SO₄ --> Na₂SO₄ +H₂O

¿Cuál es el reactivo limitante ( 1= hidróxido, 2= ácido)
Masa de sulfato sócdico

Datos (A): Na=23; S=32; H=1; O=16

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