2º BACHILLERATO/06 EQUILIBRIOS REDOX ácido nítrico y carbono El ácido nítrico concentrado reacciona con carbono produciéndose dióxido de nitrógeno, dióxido de carbono y agua.

Calcule el volumen, en litros, de dióxido de carbono, medido a 25º C y #pres mm de presión, que se desprenderá cuando reaccione #mc kg de un carbón mineral, que tiene una riqueza en carbono del #riq % con exceso de ácido nítrico.

Datos:  Masa atómica: C = 12

 

]]> 1.0000000 0.3333333 0 0 #vdi]]> <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>pres</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>70</mn><mo>,</mo><mn>90</mn><mo>)</mo><mo>*</mo><mn>10</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mc</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>8</mn><mo>,</mo><mn>15</mn><mo>)</mo><mo>/</mo><mn>10</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>riq</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>6</mn><mo>,</mo><mn>9</mn><mo>)</mo><mo>*</mo><mn>10</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mcr</mi><mo>=</mo><mi>mc</mi><mo>*</mo><mi>riq</mi><mo>*</mo><mn>10</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mold</mi><mo>=</mo><mi>mcr</mi><mo>/</mo><mn>12</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>vdi</mi><mo>=</mo><mi>mold</mi><mo>*</mo><mn>0</mn><mo>.</mo><mn>082</mn><mo>*</mo><mn>298</mn><mo>*</mo><mn>760</mn><mo>/</mo><mi>pres</mi></math></input></command></group></library></session>]]></wirisCasSession><correctAnswers><correctAnswer type="mathml"><![CDATA[<math xmlns="http://www.w3.org/1998/Math/MathML"><mo>#</mo><mi>v</mi><mi>d</mi><mi mathvariant="normal">i</mi></math>]]></correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units"><![CDATA[m, s, g, °, ', ", $, ¥, €, £, kr, Fr, ₩, ₹, руб, BTC, %, ‰, A, K, mol, cd, rad, sr, h, min, l, N, Pa, Hz, W, J, C, V, Ω, F, S, Wb, b, H, T, lx, lm, Gy, Bq, Sv, kat]]></param><param name="decimalseparators">., \,</param><param name="unitprefixes">M, k, c, m</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">0.03</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="times_operator">·</option><option name="implicit_times_operator">false</option><option name="imaginary_unit">i</option><option name="answer_parameter">true</option></options><localData><data name="inputField">textField</data><data name="gradeCompound">and</data><data name="gradeCompoundDistribution"></data><data name="casSession"></data></localData></question> Bromuro de sodio con ácido nítrico #mbr g de bromuro de sodio, NaBr, se tratan con ácido nítrico concentrado, HNO3, de densidad #da g · ml–1 y riqueza del #ra % en masa, hasta la reacción completa. En esta reacción se obtiene Br2, NO2 y NaNO3 y agua como productos de la reacción.  

  1. Calcula la molaridad de la disolución de ácido.
  2. Calcula el volumen, en cm3, de ácido nítrico necesario para completar la reacción.

DATOS: Ar (Br) = 80 u; Ar (Na) = 23 u.

]]> 1.0000000 0.3333333 0 0 1.- Molaridad del ácido = #maf2.- Volumen de ácido necesario = #vaf]]> <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mbr</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>40</mn><mo>,</mo><mn>70</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>da</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>105</mn><mo>,</mo><mn>120</mn><mo>)</mo><mo>/</mo><mn>100</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>ra</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>60</mn><mo>,</mo><mn>75</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>maf</mi><mo>=</mo><mi>da</mi><mo>*</mo><mn>1000</mn><mo>*</mo><mi>ra</mi><mo>/</mo><mo>(</mo><mn>100</mn><mo>*</mo><mn>63</mn><mo>.</mo><mn>0</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>molbr</mi><mo>=</mo><mi>mbr</mi><mo>/</mo><mn>103</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>vaf</mi><mo>=</mo><mi>molbr</mi><mo>*</mo><mn>2</mn><mo>.</mo><mn>0</mn><mo>*</mo><mn>1000</mn><mo>/</mo><mi>maf</mi></math></input></command></group></library></session>]]></wirisCasSession><correctAnswers><correctAnswer type="mathml"><![CDATA[<math xmlns="http://www.w3.org/1998/Math/MathML"><mn>1</mn><mo>.</mo><mo>-</mo><mo>&#160;</mo><mi>M</mi><mi>o</mi><mi mathvariant="normal">l</mi><mi>a</mi><mi>r</mi><mi mathvariant="normal">i</mi><mi>d</mi><mi>a</mi><mi>d</mi><mo>&#160;</mo><mi>d</mi><mi mathvariant="normal">e</mi><mi mathvariant="normal">l</mi><mo>&#160;</mo><mi>&#225;</mi><mi>c</mi><mi mathvariant="normal">i</mi><mi>d</mi><mi>o</mi><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mo>#</mo><mi mathvariant="normal">m</mi><mi>a</mi><mi>f</mi><mspace linebreak="newline"/><mn>2</mn><mo>.</mo><mo>-</mo><mo>&#160;</mo><mi mathvariant="normal">V</mi><mi>o</mi><mi mathvariant="normal">l</mi><mi>u</mi><mi mathvariant="normal">m</mi><mi mathvariant="normal">e</mi><mi>n</mi><mo>&#160;</mo><mi>d</mi><mi mathvariant="normal">e</mi><mo>&#160;</mo><mi>&#225;</mi><mi>c</mi><mi mathvariant="normal">i</mi><mi>d</mi><mi>o</mi><mo>&#160;</mo><mi>n</mi><mi mathvariant="normal">e</mi><mi>c</mi><mi mathvariant="normal">e</mi><mi mathvariant="normal">s</mi><mi>a</mi><mi>r</mi><mi mathvariant="normal">i</mi><mi>o</mi><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mo>#</mo><mi>v</mi><mi>a</mi><mi>f</mi></math>]]></correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units"><![CDATA[m, s, g, °, ', ", sr, E, K, mol, cd, rad, h, min, l, N, Pa, Hz, W, J, C, V, Ω, F, S, Wb, b, H, T, lx, lm, Gy, Bq, Sv, kat]]></param><param name="unitprefixes">M, k, c, m</param><param name="groupoperators">(,[,{</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(--log(0.02))</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="inputField">textField</data><data name="inputCompound">true</data><data name="gradeCompound">distribute</data><data name="gradeCompoundDistribution"></data><data name="casSession"/></localData></question> Clorato e hierro En medio ácido, el ión clorato, ClO3 -, oxida al hierro (II) de acuerdo con la siguiente reacción no ajustada:

ClO3 - (ac) + Fe2+(ac) + H+ (ac) → Cl- (ac) + Fe3+(ac) + H2O (l)

Determine el volumen, en ml,  de una disolución de clorato de potasio (KClO3) #cc M necesario para oxidar #mh gramos de cloruro de hierro (II) (FeCl2) cuya pureza es del #pur % en peso. 

DATOS.- Masas atómicas: Fe = 55,8 ; O = 16; Cl = 35,5 ; K = 39,1.

]]> 1.0000000 0.3333333 0 0 #vc <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>cc</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>1</mn><mo>,</mo><mn>7</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>cc</mi><mo>=</mo><mi>cc</mi><mo>*</mo><mn>1</mn><mo>.</mo><mn>0</mn><mo>/</mo><mn>10</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mh</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>5</mn><mo>,</mo><mn>20</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>pur</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>70</mn><mo>,</mo><mn>95</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mhi</mi><mo>=</mo><mi>mh</mi><mo>*</mo><mi>pur</mi><mo>/</mo><mo>(</mo><mn>100</mn><mo>*</mo><mn>126</mn><mo>.</mo><mn>8</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>vc</mi><mo>=</mo><mi>mhi</mi><mo>*</mo><mn>1000</mn><mo>/</mo><mo>(</mo><mn>6</mn><mo>*</mo><mi>cc</mi><mo>)</mo></math></input></command></group></library></session>]]></wirisCasSession><correctAnswers><correctAnswer>#vc</correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units"><![CDATA[m, s, g, °, ', ", sr, E, K, mol, cd, rad, h, min, l, N, Pa, Hz, W, J, C, V, Ω, F, S, Wb, b, H, T, lx, lm, Gy, Bq, Sv, kat]]></param><param name="unitprefixes">M, k, c, m</param><param name="groupoperators">(,[,{</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(--log(0.02))</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="inputField">textField</data><data name="gradeCompound">and</data><data name="gradeCompoundDistribution"></data><data name="casSession"/></localData></question> contenido en hierro Para determinar el contenido en hierro de cierto preparado vitamínico, donde el hierro se encuentra en forma de Fe(II), se pesaron #ma g del preparado, se disolvieron en medio ácido y se hicieron reaccionar con una disolución #cp M en permanganato potásico necesitándose, para ello, #vp mL de ésta disolución. La reacción no ajustada que tiene lugar es la siguiente:

 MnO4- (ac) + Fe2+ (ac) + H+ (ac)  ↔ Mn2+ (ac) + Fe3+ (ac) + H2O (l)  

Calcule el % de hierro (en masa) presente en el preparado vitamínico.

DATOS.- Masas atómicas: Fe=55,8.

]]> 1.0000000 0.3333333 0 0 #porc1 <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>ma</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>10</mn><mo>,</mo><mn>30</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>por</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>5</mn><mo>,</mo><mn>9</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mp1</mi><mo>=</mo><mi>ma</mi><mo>*</mo><mi>por</mi><mo>/</mo><mo>(</mo><mn>55</mn><mo>.</mo><mn>85</mn><mo>*</mo><mn>100</mn><mo>*</mo><mn>5</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>vp</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>20</mn><mo>,</mo><mn>40</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>cp</mi><mo>=</mo><mn>1</mn><mo>.</mo><mn>0</mn><mo>*</mo><mi>mp1</mi><mo>*</mo><mn>1000</mn><mo>/</mo><mi>vp</mi></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>porc1</mi><mo>=</mo><mi>cp</mi><mo>*</mo><mi>vp</mi><mo>*</mo><mn>5</mn><mo>*</mo><mn>55</mn><mo>.</mo><mn>8</mn><mo>*</mo><mn>100</mn><mo>/</mo><mo>(</mo><mn>1000</mn><mo>*</mo><mi>ma</mi><mo>)</mo></math></input></command></group></library></session>]]></wirisCasSession><correctAnswers><correctAnswer>#porc1</correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units"><![CDATA[m, s, g, °, ', ", sr, E, K, mol, cd, rad, h, min, l, N, Pa, Hz, W, J, C, V, Ω, F, S, Wb, b, H, T, lx, lm, Gy, Bq, Sv, kat]]></param><param name="unitprefixes">M, k, c, m</param><param name="groupoperators">(,[,{</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(--log(0.02))</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="inputField">textField</data><data name="gradeCompound">and</data><data name="gradeCompoundDistribution"></data><data name="casSession"/></localData></question> Dicromato-yoduro Dada la reacción redox en disolución acuosa

KI + H2SO4 + K2Cr2O7 --> K2SO4 + H2O + Cr2(SO4)3 + I2

Calcule la molaridad de la disolución de dicromato de potasio, si #vd mL de la misma reaccionan con #vy mL de una disolución que contiene #cy g/L de yoduro de potasio.

Masas atómicas: K = 39; I = 127.

]]> 1.0000000 0.3333333 0 0 #md]]> <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>vd</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>10</mn><mo>,</mo><mn>30</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>vy</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>30</mn><mo>,</mo><mn>70</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>cy</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>30</mn><mo>,</mo><mn>80</mn><mo>)</mo><mo>/</mo><mn>10</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>moly</mi><mo>=</mo><mi>cy</mi><mo>*</mo><mi>vy</mi><mo>/</mo><mn>166000</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>md</mi><mo>=</mo><mi>moly</mi><mo>*</mo><mn>1000</mn><mo>/</mo><mo>(</mo><mn>6</mn><mo>*</mo><mi>vd</mi><mo>)</mo></math></input></command></group></library><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></session>]]></wirisCasSession><correctAnswers><correctAnswer type="mathml"><![CDATA[<math xmlns="http://www.w3.org/1998/Math/MathML"><mo>#</mo><mi mathvariant="normal">m</mi><mi>d</mi></math>]]></correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units"><![CDATA[m, s, g, °, ', ", $, ¥, €, £, kr, Fr, ₩, ₹, руб, BTC, %, ‰, A, K, mol, cd, rad, sr, h, min, l, N, Pa, Hz, W, J, C, V, Ω, F, S, Wb, b, H, T, lx, lm, Gy, Bq, Sv, kat]]></param><param name="decimalseparators">., \,</param><param name="unitprefixes">M, k, c, m</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">0.03</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="times_operator">·</option><option name="implicit_times_operator">false</option><option name="imaginary_unit">i</option><option name="answer_parameter">true</option></options><localData><data name="inputField">textField</data><data name="gradeCompound">and</data><data name="gradeCompoundDistribution"></data><data name="casSession"/></localData></question> Espontaneidad en redox A la vista de los potenciales normales de reducción de la tabla siguiente, indica si son ciertas o falsas las siguientes afirmaciones

]]> 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 1.0000000 0.3333333 0 false true abc Respuesta correcta

]]> Respuesta parcialmente correcta.

]]> Respuesta incorrecta.

]]> Si añadimos #r11 a una disolución de HCl  se desprenderá hidrógeno

]]> Si añadimos #r21 a una disolución de HCl  se desprenderá hidrógeno

]]> Si añadimos #r21 a una disolución de ion #r11 se depositará #r11 metálico

]]> Si añadimos #r12 a una disolución de ion #r22 se depositará #r22 metálico

]]> Si añadimos #r13 a una disolución de ion #r23 se depositará #r23 metálico

]]> Si añadimos #r21 a una disolución de ion #r13 se depositará #r13 metálico

]]> <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>par1</mi><mo>=</mo><mo>(</mo><mo>&quot;</mo><mi>cinc</mi><mo>&quot;</mo><mo>,</mo><mo>&quot;</mo><mi>aluminio</mi><mo>&quot;</mo><mo>,</mo><mo>&quot;</mo><mi>hierro</mi><mo>&quot;</mo><mo>,</mo><mo>&quot;</mo><mi>cadmio</mi><mo>&quot;</mo><mo>,</mo><mo>&quot;</mo><mi>plomo</mi><mo>&quot;</mo><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>par2</mi><mo>=</mo><mo>(</mo><mo>&quot;</mo><mi>cobre</mi><mo>&quot;</mo><mo>,</mo><mo>&quot;</mo><mi>mercurio</mi><mo>&quot;</mo><mo>,</mo><mo>&quot;</mo><mi>plata</mi><mo>&quot;</mo><mo>,</mo><mo>&quot;</mo><mi>oro</mi><mo>&quot;</mo><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>in11</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>1</mn><mo>,</mo><mn>5</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>in12</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>1</mn><mo>,</mo><mn>5</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>in13</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>1</mn><mo>,</mo><mn>5</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>in21</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>1</mn><mo>,</mo><mn>4</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>in22</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>1</mn><mo>,</mo><mn>4</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>in23</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>1</mn><mo>,</mo><mn>4</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>r11</mi><mo>=</mo><msub><mi>par1</mi><mi>in11</mi></msub></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>r12</mi><mo>=</mo><msub><mi>par1</mi><mi>in12</mi></msub></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>r13</mi><mo>=</mo><msub><mi>par1</mi><mi>in13</mi></msub></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>r21</mi><mo>=</mo><msub><mi>par2</mi><mi>in21</mi></msub></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>r22</mi><mo>=</mo><msub><mi>par2</mi><mi>in22</mi></msub></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>r23</mi><mo>=</mo><msub><mi>par2</mi><mi>in23</mi></msub></math></input></command></group></library><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></session>]]></wirisCasSession><options><option name="precision">4</option><option name="times_operator">·</option><option name="implicit_times_operator">false</option><option name="imaginary_unit">i</option><option name="answer_parameter">true</option></options><localData><data name="casSession"></data></localData></question> Hidrogenosulfito y yodo Con objeto de averiguar la concentración de una disolución acuosa de yodo, se prepara una disolución #mhs M de hidrogenosulfito de sodio. Al tomar 50 ml de la disolución de yodo, se comprueba experimentalmente que el punto final de la reacción (usando como indicador engrudo de almidón)  se consigue con #vhs ml de aquella disolución de hidrógenosulfito de sodio. Determinar la concentración de I2, expresada en g/l de disolución.

I2 + HSO3-  -> I- + SO4-2

Dato: masa atómica del yodo = 129.6

]]> 1.0000000 0.3333333 0 0 #cy <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mhs</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>1</mn><mo>,</mo><mn>5</mn><mo>)</mo><mo>/</mo><mn>100</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>vhs</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>100</mn><mo>,</mo><mn>250</mn><mo>)</mo><mo>/</mo><mn>10</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>nmhs</mi><mo>=</mo><mi>mhs</mi><mo>*</mo><mi>vhs</mi><mo>/</mo><mn>1000</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>cy</mi><mo>=</mo><mi>nmhs</mi><mo>*</mo><mn>2</mn><mo>*</mo><mn>129</mn><mo>.</mo><mn>6</mn><mo>*</mo><mn>1000</mn><mo>/</mo><mn>50</mn></math></input></command></group></library><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></session>]]></wirisCasSession><correctAnswers><correctAnswer>#cy</correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units"><![CDATA[m, s, g, °, ', ", $, ¥, €, £, kr, Fr, ₩, ₹, руб, BTC, %, ‰, A, K, mol, cd, rad, sr, h, min, l, N, Pa, Hz, W, J, C, V, Ω, F, S, Wb, b, H, T, lx, lm, Gy, Bq, Sv, kat]]></param><param name="decimalseparators">., \,</param><param name="unitprefixes">M, k, c, m</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">0.03</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="times_operator">·</option><option name="implicit_times_operator">false</option><option name="imaginary_unit">i</option><option name="answer_parameter">true</option></options><localData><data name="inputField">textField</data><data name="gradeCompound">and</data><data name="gradeCompoundDistribution"></data><data name="casSession"></data></localData></question> nitrato de potasio y cloruro amónico El nitrato de potasio sólido reacciona, en caliente, con cloruro de amonio sólido dando lugar a cloruro de potasio (sólido) , óxido de dinitrógeno (gas) y agua líquida. Se calientan #mni g de nitrato de potasio con #mclo g de cloruro de amonio. ¿Cuál es el volumen, en litros, de gas recogido sobre agua, medido a #tc ºC y 1 atm?.

(DATOS: Presión de vapor de agua a #tc ºC = 31'82 mm Hg. Ar: K=39 N=14 O=16 Cl=35,45 H=1)

]]> 1.0000000 0.3333333 0 0 #vdi]]> <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mni</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>5</mn><mo>,</mo><mn>20</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mclo</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>5</mn><mo>,</mo><mn>30</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>tc</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>20</mn><mo>,</mo><mn>60</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>tk</mi><mo>=</mo><mi>tc</mi><mo>+</mo><mn>273</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>molni</mi><mo>=</mo><mi>mni</mi><mo>/</mo><mn>101</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>molclo</mi><mo>=</mo><mi>mclo</mi><mo>/</mo><mn>53</mn><mo>.</mo><mn>5</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>p</mi><mo>=</mo><mn>1</mn><mo>-</mo><mo>(</mo><mn>31</mn><mo>.</mo><mn>82</mn><mo>/</mo><mn>760</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><apply><csymbol definitionURL="http://www.wiris.com/XML/csymbol">if</csymbol><mrow><mi>molni</mi><mo>&gt;</mo><mi>molclo</mi></mrow><mrow><mi>vdi</mi><mo>=</mo><mi>molclo</mi><mo>*</mo><mn>0</mn><mo>.</mo><mn>082</mn><mo>*</mo><mi>tk</mi><mo>/</mo><mi>p</mi></mrow><mrow><mi>vdi</mi><mo>=</mo><mi>molni</mi><mo>*</mo><mn>0</mn><mo>.</mo><mn>082</mn><mo>*</mo><mi>tk</mi><mo>/</mo><mi>p</mi></mrow></apply></math></input></command></group></library></session>]]></wirisCasSession><correctAnswers><correctAnswer type="mathml"><![CDATA[<math xmlns="http://www.w3.org/1998/Math/MathML"><mo>#</mo><mi>v</mi><mi>d</mi><mi mathvariant="normal">i</mi></math>]]></correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units"><![CDATA[m, s, g, °, ', ", sr, E, K, mol, cd, rad, h, min, l, N, Pa, Hz, W, J, C, V, Ω, F, S, Wb, b, H, T, lx, lm, Gy, Bq, Sv, kat]]></param><param name="unitprefixes">M, k, c, m</param><param name="groupoperators">(,[,{</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(--log(0.02))</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="inputField">textField</data><data name="gradeCompound">and</data><data name="gradeCompoundDistribution"></data><data name="casSession"/></localData></question> Peramanganato El permanganato de potasio oxida al agua oxigenada en medio ácido, transformándose en una sal de manganeso (II) y desprendiendo oxígeno . ¿Qué cantidad de permanganato de potasio, en gramos, serán necesaria para oxidar #ma gramos de agua oxigenada del  #c %?

Datos: masas atómicas : K= 39.1; Mn = 54.9; O=16)

]]> 1.0000000 0.3333333 0 0 #mp <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>ma</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>20</mn><mo>,</mo><mn>60</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>c</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>2</mn><mo>,</mo><mn>9</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mp</mi><mo>=</mo><mi>ma</mi><mo>*</mo><mo>(</mo><mi>c</mi><mo>/</mo><mn>100</mn><mo>)</mo><mo>*</mo><mo>(</mo><mn>2</mn><mo>*</mo><mn>157</mn><mo>.</mo><mn>9</mn><mo>/</mo><mn>170</mn><mo>)</mo></math></input></command></group></library></session>]]></wirisCasSession><correctAnswers><correctAnswer>#mp</correctAnswer></correctAnswers><assertions><assertion name="syntax_expression"/><assertion name="equivalent_symbolic"/></assertions><options><option name="relative_tolerance">true</option><option name="tolerance">10^(--log(0.02))</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="inputField">textField</data><data name="gradeCompound">and</data><data name="gradeCompoundDistribution"></data><data name="casSession"/></localData></question> Perbromato cinc La siguiente reacción tiene lugar en medio ácido: BrO4− + Zn  → Br − + Zn2+

Calcule la riqueza, en %, de una muestra de Zn si #mm g de la misma reacciona con #vd mL de una disolución #md M de iones BrO4 −.

Masa atómica: Zn = 65’4.

 

]]> 1.0000000 0.3333333 0 0 #por <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>vd</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>15</mn><mo>,</mo><mn>35</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>md</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>1</mn><mo>,</mo><mn>9</mn><mo>)</mo><mo>/</mo><mn>10</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>nmz</mi><mo>=</mo><mi>vd</mi><mo>*</mo><mi>md</mi><mo>/</mo><mn>1000</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>ngz</mi><mo>=</mo><mi>nmz</mi><mo>*</mo><mn>4</mn><mo>*</mo><mn>65</mn><mo>.</mo><mn>4</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>por</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>70</mn><mo>,</mo><mn>98</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mm</mi><mo>=</mo><mi>ngz</mi><mo>*</mo><mn>100</mn><mo>.</mo><mn>0</mn><mo>/</mo><mi>por</mi></math></input></command></group></library><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></session>]]></wirisCasSession><correctAnswers><correctAnswer>#por</correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units"><![CDATA[m, s, g, °, ', ", $, ¥, €, £, kr, Fr, ₩, ₹, руб, BTC, %, ‰, A, K, mol, cd, rad, sr, h, min, l, N, Pa, Hz, W, J, C, V, Ω, F, S, Wb, b, H, T, lx, lm, Gy, Bq, Sv, kat]]></param><param name="decimalseparators">., \,</param><param name="unitprefixes">M, k, c, m</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="float_format">,mg</option><option name="tolerance">0.03</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="times_operator"></option><option name="implicit_times_operator">false</option><option name="imaginary_unit"></option><option name="answer_parameter">true</option></options><localData><data name="inputField">textField</data><data name="gradeCompound">and</data><data name="gradeCompoundDistribution"></data><data name="casSession"></data></localData></question> Permanganato con sulfúrico En medio sulfúrico, KMnO4 ataca al H2O2 dando, entre otros productos, MnSO4 y O2 (g). Ajustar la reacción. Si tratamos #mp g de permanganato de potasio con 250 ml de un agua oxigenada de densidad #da g/ml y del #ra % en H2O2, ¿Qué volumen, en litros, ocupa el oxigeno obtenido a #pre mmHg y 27 ºC. (Ar: K=39 Mn=55 O=16 H=1).

]]> 1.0000000 0.3333333 0 0 #volo]]> <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mp</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>5</mn><mo>,</mo><mn>20</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>da</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>101</mn><mo>,</mo><mn>108</mn><mo>)</mo><mo>/</mo><mn>100</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>ra</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>10</mn><mo>,</mo><mn>40</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>pre</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>600</mn><mo>,</mo><mn>800</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>pra</mi><mo>=</mo><mi>pre</mi><mo>/</mo><mn>760</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>molp</mi><mo>=</mo><mi>mp</mi><mo>/</mo><mn>158</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mola</mi><mo>=</mo><mi>da</mi><mo>*</mo><mn>250</mn><mo>*</mo><mi>ra</mi><mo>/</mo><mo>(</mo><mn>100</mn><mo>*</mo><mn>34</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><apply><csymbol definitionURL="http://www.wiris.com/XML/csymbol">if</csymbol><mrow><mo>(</mo><mi>molp</mi><mo>*</mo><mn>5</mn><mo>/</mo><mn>2</mn><mo>)</mo><mo>&gt;</mo><mi>mola</mi></mrow><mrow><mi>volo</mi><mo>=</mo><mi>mola</mi><mo>*</mo><mn>0</mn><mo>.</mo><mn>082</mn><mo>*</mo><mn>300</mn><mo>/</mo><mi>pra</mi></mrow><mrow><mi>volo</mi><mo>=</mo><mi>molp</mi><mo>*</mo><mn>5</mn><mo>*</mo><mn>0</mn><mo>.</mo><mn>082</mn><mo>*</mo><mn>300</mn><mo>/</mo><mo>(</mo><mi>pra</mi><mo>*</mo><mn>2</mn><mo>)</mo></mrow></apply></math></input></command></group></library></session>]]></wirisCasSession><correctAnswers><correctAnswer type="mathml"><![CDATA[<math xmlns="http://www.w3.org/1998/Math/MathML"><mo>#</mo><mi>v</mi><mi>o</mi><mi mathvariant="normal">l</mi><mi>o</mi></math>]]></correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units"><![CDATA[m, s, g, °, ', ", sr, E, K, mol, cd, rad, h, min, l, N, Pa, Hz, W, J, C, V, Ω, F, S, Wb, b, H, T, lx, lm, Gy, Bq, Sv, kat]]></param><param name="unitprefixes">M, k, c, m</param><param name="groupoperators">(,[,{</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(--log(0.02))</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="inputField">textField</data><data name="gradeCompound">and</data><data name="gradeCompoundDistribution"></data><data name="casSession"/></localData></question> Pilas Con la siguiente relación de potenciales normales de reducción. Indica si las siguientes pilas funcionarán, no lo harán o están mal escritas

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 1.0000000 0.3333333 0 true Respuesta correcta

]]> Respuesta parcialmente correcta.

]]> Respuesta incorrecta.

]]> Ca / Ca+2 (1M) / / Pb+2 (1M) / Pb

]]> Correcta Cu / Cu+2 (1M) / / Pb+2 (1M) / Pb

]]> Incorrecta Hg +2  / Hg (1M) / / Pb+2 (1M) / Pb

]]> Incorrecta Ag+ /  Ag (1M) / /Pb+2 (1M) / Pb

]]> Incorrecta H2 / 2H+ (1M) / /Ni+2 (1M) / Ni

]]> Incorrecta Al / Al+3 (1M) / /Ag+ (1M) / Ag

]]> Correcta sulfito y dicromato Se quieren oxidar #ms g de sulfito de sodio (Na2SO3) con una disolución #cd M de dicromato de potasio (K2Cr2O7) en medio ácido sulfúrico, de acuerdo con la siguiente reacción no ajustada:

 Na2SO3 + K2Cr2O7 + H2SO4→ Na2SO4 + Cr2(SO4)3 + H2O + K2SO4

Se pide:

  1. El volumen de disolución de K2Cr2O7 , en ml, necesario para la oxidación completa del sulfito de sodio.
  2. Los gramos de K2SO4 que se obtienen.

Datos: Masas moleculares Na2SO3: 126 ; K2Cr2O7: 294 ; K2SO4: 174.

]]> 1.0000000 0.3333333 0 0 volumen dicromato =#vdMasa sulfato = #ms2]]> <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>ms</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>2</mn><mo>,</mo><mn>12</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>cd</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>2</mn><mo>,</mo><mn>12</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>cd</mi><mo>=</mo><mi>cd</mi><mo>*</mo><mn>1</mn><mo>.</mo><mn>0</mn><mo>/</mo><mn>10</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mold</mi><mo>=</mo><mi>ms</mi><mo>/</mo><mo>(</mo><mn>126</mn><mo>*</mo><mn>3</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>vd</mi><mo>=</mo><mn>1000</mn><mo>.</mo><mn>0</mn><mo>*</mo><mi>mold</mi><mo>/</mo><mi>cd</mi></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>ms2</mi><mo>=</mo><mn>1</mn><mo>.</mo><mn>0</mn><mo>*</mo><mi>ms</mi><mo>*</mo><mn>174</mn><mo>/</mo><mo>(</mo><mn>126</mn><mo>*</mo><mn>3</mn><mo>)</mo></math></input></command></group></library></session>]]></wirisCasSession><correctAnswers><correctAnswer type="mathml"><![CDATA[<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>v</mi><mi>o</mi><mi>l</mi><mi>u</mi><mi mathvariant="normal">m</mi><mi mathvariant="normal">e</mi><mi>n</mi><mo>&#xA0;</mo><mi>d</mi><mi mathvariant="normal">i</mi><mi>c</mi><mi>r</mi><mi>o</mi><mi mathvariant="normal">m</mi><mi>a</mi><mi>t</mi><mi>o</mi><mo>&#xA0;</mo><mo>=</mo><mo>#</mo><mi>v</mi><mi>d</mi><mspace linebreak="newline"/><mi>M</mi><mi>a</mi><mi mathvariant="normal">s</mi><mi>a</mi><mo>&#xA0;</mo><mi mathvariant="normal">s</mi><mi>u</mi><mi>l</mi><mi>f</mi><mi>a</mi><mi>t</mi><mi>o</mi><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mo>#</mo><mi>ms</mi><mn>2</mn></math>]]></correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units">m, s, g, °, ', &quot;</param><param name="decimalseparators">., \,</param><param name="unitprefixes">M, k, c, m</param><param name="groupoperators">(,[,{</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(--log(0.02))</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option><option name="answer_parameter">true</option></options><localData><data name="inputField">textField</data><data name="gradeCompound">distribute</data><data name="gradeCompoundDistribution"></data><data name="casSession"/><data name="inputCompound">true</data></localData></question> Valoración hierro (II) con dicromato Una muestra mineral de #m g que contiene hierro se disuelve en HCl y se obtiene cloruro de hierro (II). Se ajusta el volumen de ésta disolución a 50 mL añadiendo agua y se valora con dicromato de potasio #md M en medio ácido. Sabiendo que la valoración termina cuando se han añadido #vf mL de dicromato de potasio y que la forma final de cromo en el proceso redox es Cr3+

  1.  Determina la concentración molar del cloruro de hierro (II) en la disolución valorada.
  2.  Determina el tanto por ciento en peso de hierro en la muestra mineral analizada.

 

]]> 1.0000000 0.3333333 0 0 M FeII = #mhiPorcentaje hierro =#por]]> <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>vf</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>200</mn><mo>,</mo><mn>350</mn><mo>)</mo><mo>/</mo><mn>10</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>md</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>1</mn><mo>,</mo><mn>4</mn><mo>)</mo><mo>/</mo><mn>10</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>por</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>60</mn><mo>,</mo><mn>90</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>molhi</mi><mo>=</mo><mn>6</mn><mo>*</mo><mi>vf</mi><mo>*</mo><mi>md</mi><mo>/</mo><mn>1000</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mhi</mi><mo>=</mo><mi>molhi</mi><mo>*</mo><mn>1000</mn><mo>/</mo><mn>50</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mashi</mi><mo>=</mo><mi>molhi</mi><mo>*</mo><mn>55</mn><mo>.</mo><mn>8</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>m</mi><mo>=</mo><mi>mashi</mi><mo>*</mo><mn>100</mn><mo>/</mo><mi>por</mi></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></library></session>]]></wirisCasSession><correctAnswers><correctAnswer type="mathml"><![CDATA[<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>M</mi><mo>&#xA0;</mo><mfenced><mrow><mi>F</mi><mi mathvariant="normal">e</mi><mfenced><mrow><mi>I</mi><mi>I</mi></mrow></mfenced></mrow></mfenced><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mo>#</mo><mi mathvariant="normal">m</mi><mi mathvariant="normal">h</mi><mi mathvariant="normal">i</mi><mspace linebreak="newline"/><mi>P</mi><mi>o</mi><mi>r</mi><mi>c</mi><mi mathvariant="normal">e</mi><mi>n</mi><mi>t</mi><mi>a</mi><mi mathvariant="normal">j</mi><mi mathvariant="normal">e</mi><mo>&#xA0;</mo><mi mathvariant="normal">h</mi><mi mathvariant="normal">i</mi><mi mathvariant="normal">e</mi><mi>r</mi><mi>r</mi><mi>o</mi><mo>&#xA0;</mo><mo>=</mo><mo>#</mo><mi>p</mi><mi>o</mi><mi>r</mi><mspace linebreak="newline"/></math>]]></correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units"><![CDATA[m, s, g, °, ', ", $, ¥, €, £, kr, Fr, ₩, ₹, руб, BTC, %, ‰, A, K, mol, cd, rad, sr, h, min, l, N, Pa, Hz, W, J, C, V, Ω, F, S, Wb, b, H, T, lx, lm, Gy, Bq, Sv, kat]]></param><param name="decimalseparators">., \,</param><param name="unitprefixes">M, k, c, m</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">0.03</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="times_operator">·</option><option name="implicit_times_operator">false</option><option name="imaginary_unit">i</option><option name="answer_parameter">true</option></options><localData><data name="inputField">textField</data><data name="gradeCompound">distribute</data><data name="gradeCompoundDistribution"></data><data name="casSession"/><data name="inputCompound">true</data></localData></question> Ver pares oxidación/reducción Indica si será posible o no la reacción entre:

(Usa la tabla de potenciales que hay en la plataforma)

]]> 1.0000000 0.3333333 0 true Respuesta correcta

]]> Respuesta parcialmente correcta.

]]> Respuesta incorrecta.

]]> Ni2+ + Li

]]> Si Sn2+ + Na+

]]> No Cl- + Fe3+

]]> No Cu2+ + Fe

]]> Si Ag+ + H2O2

]]> Si Cu + I-

]]> No 2º BACHILLERATO/06 EQUILIBRIOS REDOX/ELECTROLISIS Calcular número de oxidación Una disolución acuosa de una sal de un metal se electroliza durante dos horas con una corriente de #co A. Calcular la carga del ion metálico en la disolución, sabiendo que en el cátodo se han depositado #ma g de  metal durante la electrolisis.

Masa atómica del metal = #mat

]]> 1.0000000 0.3333333 0 0 #v <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mat</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>60</mn><mo>,</mo><mn>140</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>co</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>2</mn><mo>,</mo><mn>9</mn><mo>)</mo><mo>/</mo><mn>10</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>v</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>1</mn><mo>,</mo><mn>5</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>ma</mi><mo>=</mo><mi>mat</mi><mo>*</mo><mi>co</mi><mo>*</mo><mn>7200</mn><mo>/</mo><mo>(</mo><mn>96500</mn><mo>*</mo><mi>v</mi><mo>)</mo></math></input></command></group></library><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></session>]]></wirisCasSession><correctAnswers><correctAnswer>#v</correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units">m, s, g, °, ', &quot;</param><param name="decimalseparators">., \,</param><param name="unitprefixes">M, k, c, m</param><param name="groupoperators">(,[,{</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(--log(0.02))</option><option name="relative_tolerance">true</option><option name="precision">3</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option><option name="answer_parameter">true</option></options><localData><data name="inputField">textField</data><data name="gradeCompound">and</data><data name="gradeCompoundDistribution"></data><data name="casSession"/></localData></question> Dorado Para cubrir de oro una pieza de joyería son necesarios #masa g de metal. Calcula el tiempo, en segundos, durante el que una corriente de #ic A debe estar circulando por una cuba electrolítica que contiene una disolución acuosa de cloruro de oro (III) de concentración 0.3 M.

Datos: Au = 197 ; Cl = 35,5.

]]> 1.0000000 0.3333333 0 0 #t <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>masa</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>4</mn><mo>,</mo><mn>28</mn><mo>)</mo><mo>/</mo><mn>100</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>ic</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>2</mn><mo>,</mo><mn>18</mn><mo>)</mo><mo>/</mo><mn>100</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>t</mi><mo>=</mo><mi>masa</mi><mo>*</mo><mn>96500</mn><mo>*</mo><mn>3</mn><mo>/</mo><mo>(</mo><mn>197</mn><mo>*</mo><mi>ic</mi><mo>)</mo></math></input></command></group></library></session>]]></wirisCasSession><correctAnswers><correctAnswer>#t</correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units"><![CDATA[m, s, g, °, ', ", sr, E, K, mol, cd, rad, h, min, l, N, Pa, Hz, W, J, C, V, Ω, F, S, Wb, b, H, T, lx, lm, Gy, Bq, Sv, kat]]></param><param name="unitprefixes">M, k, c, m</param><param name="groupoperators">(,[,{</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(--log(0.02))</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="inputField">textField</data><data name="gradeCompound">and</data><data name="gradeCompoundDistribution"></data><data name="casSession"/></localData></question> electrolisis cobre Se hace pasar una corriente eléctrica de #cor amperios durante #t horas a través de una celda electrolítica que contiene una disolución acuosa de CuCl2 . Calcule:

  1. La masa de cobre metálico, en gramos, depositado en el cátodo.
  2. El volumen de Cl2 , en litros, medido en condiciones normales, que se genera en el ánodo.

Datos: F = 96500 C. Masa atómica: Cu = 63’5

]]> 1.0000000 0.3333333 0 0 Masa de cobre = #mcuVolumen de cloro = #vcl]]> <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>cor</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>2</mn><mo>,</mo><mn>8</mn><mo>)</mo><mo>/</mo><mn>10</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>t</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>2</mn><mo>,</mo><mn>5</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mcu</mi><mo>=</mo><mn>63</mn><mo>.</mo><mn>5</mn><mo>*</mo><mi>cor</mi><mo>*</mo><mi>t</mi><mo>*</mo><mn>3600</mn><mo>/</mo><mo>(</mo><mn>96500</mn><mo>*</mo><mn>2</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>vcl</mi><mo>=</mo><mn>22</mn><mo>.</mo><mn>4</mn><mo>*</mo><mi>cor</mi><mo>*</mo><mi>t</mi><mo>*</mo><mn>3600</mn><mo>/</mo><mo>(</mo><mn>96500</mn><mo>*</mo><mn>2</mn><mo>)</mo></math></input></command></group></library></session>]]></wirisCasSession><correctAnswers><correctAnswer type="mathml"><![CDATA[<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>M</mi><mi>a</mi><mi mathvariant="normal">s</mi><mi>a</mi><mo>&#160;</mo><mi>d</mi><mi mathvariant="normal">e</mi><mo>&#160;</mo><mi>c</mi><mi>o</mi><mi mathvariant="normal">b</mi><mi>r</mi><mi mathvariant="normal">e</mi><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mo>#</mo><mi mathvariant="normal">m</mi><mi>c</mi><mi>u</mi><mspace linebreak="newline"/><mi mathvariant="normal">V</mi><mi>o</mi><mi mathvariant="normal">l</mi><mi>u</mi><mi mathvariant="normal">m</mi><mi mathvariant="normal">e</mi><mi>n</mi><mo>&#160;</mo><mi>d</mi><mi mathvariant="normal">e</mi><mo>&#160;</mo><mi>cl</mi><mi>o</mi><mi>r</mi><mi>o</mi><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mo>#</mo><mi>v</mi><mi>cl</mi></math>]]></correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units"><![CDATA[m, s, g, °, ', ", sr, E, K, mol, cd, rad, h, min, l, N, Pa, Hz, W, J, C, V, Ω, F, S, Wb, b, H, T, lx, lm, Gy, Bq, Sv, kat]]></param><param name="unitprefixes">M, k, c, m</param><param name="groupoperators">(,[,{</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(--log(0.02))</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="inputField">textField</data><data name="inputCompound">true</data><data name="gradeCompound">distribute</data><data name="gradeCompoundDistribution"></data><data name="casSession"/></localData></question> Electrolisis de nitrato de cobalto

Al pasar una corriente eléctrica por una disolución acuosa de nitrato de cobalto (II) se desprende oxígeno en el ánodo y se deposita cobalto en el cátodo. Calcula:

  1. La intensidad de la corriente, en amperios, que se necesita para depositar #mco g de Co de una disolución acuosa de Co(NO3)2 en #t minutos.
  2. El volumen de oxígeno gaseoso, en litros, medido en condiciones normales, que se desprende en el ánodo.

Datos: F = 96500 C. Masas atómicas: N = 14; O = 16; Co = 59

 

]]> 1.0000000 0.3333333 0 0 Intensidad de corriente =#icVolumen oxígeno = #vo]]> <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mco</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>5</mn><mo>,</mo><mn>20</mn><mo>)</mo><mo>/</mo><mn>10</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>t</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>5</mn><mo>,</mo><mn>16</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>ic</mi><mo>=</mo><mi>mco</mi><mo>*</mo><mn>2</mn><mo>*</mo><mn>96500</mn><mo>/</mo><mo>(</mo><mn>59</mn><mo>*</mo><mi>t</mi><mo>*</mo><mn>60</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>vo</mi><mo>=</mo><mn>22</mn><mo>.</mo><mn>4</mn><mo>*</mo><mi>mco</mi><mo>/</mo><mo>(</mo><mn>59</mn><mo>*</mo><mn>2</mn><mo>)</mo></math></input></command></group></library></session>]]></wirisCasSession><correctAnswers><correctAnswer type="mathml"><![CDATA[<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>I</mi><mi>n</mi><mi>t</mi><mi mathvariant="normal">e</mi><mi>n</mi><mi mathvariant="normal">s</mi><mi mathvariant="normal">i</mi><mi>d</mi><mi>a</mi><mi>d</mi><mo>&#160;</mo><mi>d</mi><mi mathvariant="normal">e</mi><mo>&#160;</mo><mi>c</mi><mi>o</mi><mi>r</mi><mi>r</mi><mi mathvariant="normal">i</mi><mi mathvariant="normal">e</mi><mi>n</mi><mi>t</mi><mi mathvariant="normal">e</mi><mo>&#160;</mo><mo>=</mo><mo>#</mo><mi mathvariant="normal">i</mi><mi>c</mi><mspace linebreak="newline"/><mi mathvariant="normal">V</mi><mi>o</mi><mi mathvariant="normal">l</mi><mi>u</mi><mi mathvariant="normal">m</mi><mi mathvariant="normal">e</mi><mi>n</mi><mo>&#160;</mo><mi>o</mi><mi>x</mi><mi>&#237;</mi><mi mathvariant="normal">g</mi><mi mathvariant="normal">e</mi><mi>n</mi><mi>o</mi><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mo>#</mo><mi>v</mi><mi>o</mi></math>]]></correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units"><![CDATA[m, s, g, °, ', ", sr, E, K, mol, cd, rad, h, min, l, N, Pa, Hz, W, J, C, V, Ω, F, S, Wb, b, H, T, lx, lm, Gy, Bq, Sv, kat]]></param><param name="unitprefixes">M, k, c, m</param><param name="groupoperators">(,[,{</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(--log(0.02))</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="inputField">textField</data><data name="inputCompound">true</data><data name="gradeCompound">distribute</data><data name="gradeCompoundDistribution"></data><data name="casSession"/></localData></question> electrolisis plata Se realiza la electrolisis de #vol  litros de una disolución de nitrato de plata #conc M haciendo pasar una corriente eléctrica de #ic amperios durante #t horas. Calcule: a) La masa de plata que se deposita en el cátodo. b) La concentración de iones Ag+ que queda en la disolución una vez finalizada la electrolisis. Datos: F = 96500 C. Masas atómicas: Ag = 108.

]]> 1.0000000 0.3333333 0 0 masa de plata =#mplaconc plata = #cpla]]> <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>vol</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>2</mn><mo>,</mo><mn>6</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>conc</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>2</mn><mo>,</mo><mn>15</mn><mo>)</mo><mo>/</mo><mn>10</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>ic</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>0</mn><mo>.</mo><mn>2</mn><mo>,</mo><mn>0</mn><mo>.</mo><mn>8</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>t</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>1</mn><mo>,</mo><mn>4</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>carga</mi><mo>=</mo><mi>ic</mi><mo>*</mo><mi>t</mi><mo>*</mo><mn>3600</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mpla</mi><mo>=</mo><mn>108</mn><mo>*</mo><mi>carga</mi><mo>/</mo><mn>96500</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mplao</mi><mo>=</mo><mi>vol</mi><mo>*</mo><mi>conc</mi></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mplac</mi><mo>=</mo><mi>mpla</mi><mo>/</mo><mn>108</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>cpla</mi><mo>=</mo><mo>(</mo><mi>mplao</mi><mo>-</mo><mi>mplac</mi><mo>)</mo><mo>/</mo><mi>vol</mi></math></input></command></group></library><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"/></input></command></group></session>]]></wirisCasSession><correctAnswers><correctAnswer type="mathml"><![CDATA[<math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">m</mi><mi>a</mi><mi mathvariant="normal">s</mi><mi>a</mi><mo>&#xA0;</mo><mi>d</mi><mi mathvariant="normal">e</mi><mo>&#xA0;</mo><mi>p</mi><mi>l</mi><mi>a</mi><mi>t</mi><mi>a</mi><mo>&#xA0;</mo><mo>=</mo><mo>#</mo><mi mathvariant="normal">m</mi><mi>p</mi><mi>l</mi><mi>a</mi><mspace linebreak="newline"/><mi>c</mi><mi>o</mi><mi>n</mi><mi>c</mi><mo>&#xA0;</mo><mi>p</mi><mi>l</mi><mi>a</mi><mi>t</mi><mi>a</mi><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mo>#</mo><mi>c</mi><mi>p</mi><mi>l</mi><mi>a</mi></math>]]></correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units">m, s, g, °, ', &quot;</param><param name="decimalseparators">., \,</param><param name="unitprefixes">M, k, c, m</param><param name="groupoperators">(,[,{</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(--log(0.02))</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option><option name="answer_parameter">true</option></options><localData><data name="inputField">textField</data><data name="inputCompound">true</data><data name="gradeCompound">distribute</data><data name="gradeCompoundDistribution"></data><data name="casSession"/></localData></question> Plateado Se electroliza una disolución de nitrato de plata durante #t h con una corriente constante. Después del proceso se han depositado #mpl g de plata. Calcula la intensidad de la corriente.

Datos: A(Ag) = 108

]]> 1.0000000 0.3333333 0 0 #ic]]> <question><wirisCasSession><![CDATA[<session lang="es" version="2.0"><library closed="false"><mtext style="color:#ffc800" xml:lang="es">variables</mtext><group><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>t</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>2</mn><mo>,</mo><mn>7</mn><mo>)</mo></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>mpl</mi><mo>=</mo><mi>aleatorio</mi><mo>(</mo><mn>100</mn><mo>,</mo><mn>180</mn><mo>)</mo><mo>/</mo><mn>10</mn><mo>.</mo><mn>0</mn></math></input></command><command><input><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>ic</mi><mo>=</mo><mi>mpl</mi><mo>*</mo><mn>96500</mn><mo>/</mo><mo>(</mo><mn>108</mn><mo>*</mo><mn>3600</mn><mo>*</mo><mi>t</mi><mo>)</mo></math></input></command></group></library></session>]]></wirisCasSession><correctAnswers><correctAnswer type="mathml"><![CDATA[<math xmlns="http://www.w3.org/1998/Math/MathML"><mo>#</mo><mi mathvariant="normal">i</mi><mi>c</mi></math>]]></correctAnswer></correctAnswers><assertions><assertion name="syntax_quantity"><param name="units"><![CDATA[m, s, g, °, ', ", sr, E, K, mol, cd, rad, h, min, l, N, Pa, Hz, W, J, C, V, Ω, F, S, Wb, b, H, T, lx, lm, Gy, Bq, Sv, kat]]></param><param name="unitprefixes">M, k, c, m</param><param name="groupoperators">(,[,{</param></assertion><assertion name="equivalent_symbolic"/></assertions><options><option name="tolerance">10^(--log(0.02))</option><option name="relative_tolerance">true</option><option name="precision">4</option><option name="implicit_times_operator">false</option><option name="times_operator">·</option><option name="imaginary_unit">i</option></options><localData><data name="inputField">textField</data><data name="gradeCompound">and</data><data name="gradeCompoundDistribution"></data><data name="casSession"/></localData></question>